Question

1) Block A started on the left, and block B on the right. The two moved towards the middle and collided.The image above depicts the result of the two blocks colliding.

A) What is the total initial momentum of the blocks?

B) What is the total final momentum of the blocks?

C) What is the total initial kinetic energy of the blocks?

D) What is the total final kinetic energy of the blocks?

2) What type of collision is this? Use your answers from the previous question to explain.

3) Block A started on the left, and block B on the right. The two moved towards the middle and collided.The image above depicts the result of the two blocks colliding.

A) What is the total initial momentum of the blocks?

B) What is the total final momentum of the blocks?

C) What is the total initial kinetic energy of the blocks?

D) What is the total final kinetic energy of the blocks?

4) What type of collision is this? Use your answers from the previous question to explain.

5) Block A started on the left, and block B on the right. The two moved towards the middle and collided.The image above depicts the result of the two blocks colliding.

A) What is the total initial momentum of the blocks?

B) What is the total final momentum of the blocks?

C) What is the total initial kinetic energy of the blocks?

D) What is the total final kinetic energy of the blocks?

6) What type of collision is this? Use your answers from the previous question to explain.

7) In the image above, Calculate what should the mass of B be to cause mass A to come to a stop after the collision?

8) In the image above:

A) Calculate what range can the mass of B be to cause mass A to bounce off after the collision.

B) Calculate what range can the mass of B be to cause mass A to continue forward after the collision.

exploration of physics theory experiment guide O Velocity vector On/Off A (K) O CM location On/Off 24.6 m B Time (sec): 22.50 B Total 20 A coef of restitution 0.00 Avelocity (m/s) 3.0 Amass (kg) 6.0 B velocity (m/s) -2.0 B mass (kg) 4.0 Block B Block A initial momentum (kg-m/s) 18.0 -8.0 final momentum (kg-m/s) final velocity (m/s) 6.0 4.0 1.0 1.0 momentum (kg m/s) exploration of physics theory guide experiment O Velocity vector On/Off (K) O CM location On/Off B A Cursor Position Time (sec): 21.70 20 A B Total coef of restitution 1.00 Avelocity (m/s) 3.0 Amass (kg) 6.0 B velocity (m/s) -2.0 B mass (kg) 4.0 Block A Block B initial momentum (kg'm/s) 18.0 -8.0 final momentum (kg-m/s) 16.0 -6.0 final velocity (m/s) -1.0 4.0 momentum (kg-m/s) exploration of physics theory guide experiment O Velocity vector On/Off O CM location On/Off B Time (sec): 8.20 29.6 m 20 B Total A coef of restitution 0.50 A velocity (m/s) ПО 3.0 A mass (kg) 6.0 B velocity (m/s) -2.0 B mass (kg) 4.0 Block A Block B initial momentum (kg*m/s) 18.0 -8.0 final momenturm (kg-m/s) 0.0 10.0 final velocity (m/s) 0.0 2.5 momentum (kg-m/s) exploration of physics experiment theory guide A B O Velocity ve ctor On/Off (K) O CM location On/Off 23.3 m Time (sec): 0.00 20 A B Total coef of restitution 1.00 Avelocity (m/s) ПП 6.0 A mass (kg) 6.0 B velocity (m/s) 0.0 B mass (kg) 4.0 Block A Block B initial momentum (kg'm/s) ? ? final momentum (kg.m/s) ? final velocity (m/s) ? ? A momentum (kg-m/s)

Answer 1

DO NOT POST THESE MANY QUESTIONS AT ONCE PLEASE.

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POINTS TO REMEMBER:

In elastic collision, both momentum and kinetic energy are conserved

In inelastic collision, momentum is conserved but kinetic energy is not.

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1)

A) Total initial momentum = 18 - 8 = 10 kg.m/s

B) Total final momentum = 6 + 4 = 10 Kg.m/s

C) total initial kinetic energy = 1/2*6*3² + 1/2*4 * (-2)² = 35 J

D) total final kinetic energy = 1/2*6*1 + 1/2*4*1 = 5 J

2) As we can see that momentum is same but kinetic energy is not same means energy has lost means this is a case of inelastic collision.

3)

A) Total initial momentum = 18 - 8 = 10 kg.m/s

B) Total final momentum = -6 + 16 = 10 Kg.m/s

C) total initial kinetic energy = 1/2*6*3² + 1/2*4 * (-2)² = 35 J

D) total final kinetic energy = 1/2*6*1 + 1/2*4*4² = 35 J

4) As we can see that momentum is same and kinetic energy is also same means both momentum and energy are conserved, therefore this is an elastic collision.

5)

A) Total initial momentum = 18 - 8 = 10 kg.m/s

B) Total final momentum = 0 + 10 = 10 Kg.m/s

C) total initial kinetic energy = 1/2*6*3² + 1/2*4 * (-2)² = 35 J

D) total final kinetic energy = 1/2*6*0 + 1/2*4*2.5² = 12.5 J

6) As we can see that momentum is same but kinetic energy is not same means energy has lost means this is a case of inelastic collision.