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A 2.3 kg block slides along a frictionless surface at 1.3 m/s . A second block,...

A 2.3 kg block slides along a frictionless surface at 1.3 m/s . A second block, sliding at a faster 4.0 m/s , collides with the first from behind and sticks to it. The final velocity of the combined blocks is 2.3 m/s .

What was the mass of the second block?

m2=

0 0
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Answer #1

nie,+ m₂ m₂ = (mm)N 2.3x1.3 + my a (2.3+ m2) 2.1 2.99 + 4 m₂ = 4 m₂ = 5.29+2.392 4m, - 2.3m = 5.29-299, 1.7 m₂ = 2.3 m2 2.3 1

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