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A 1.4 kg block slides along a frictionless surface at 1.1 m/s . A second block,...

A 1.4 kg block slides along a frictionless surface at 1.1 m/s . A second block, sliding at a faster 4.3 m/s , collides with the first from behind and sticks to it. The final velocity of the combined blocks is 2.3 m/s . What was the mass of the second block?

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Answer #1

Let m1 and m2 be the mass of the first and the second block respectively. Let v1 and v2 be the initial velocities of the two blocks. The initial momentum of the system of two blocks is

After the collision, the two blocks combined to form a single block of mass m1+m2. Let v be the velocity of the combined blocks. The momentum of the system is

Applying the conservation of momentum

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