please be descriptive so i actually understand it.
This is a case of inelastic collision ,where only momentum is
conserved always.[not energy]
So,
v1 = 1.3 m/s , v2 = 4.2 m/s
m1 = 2.4 kg, to find , m2= ??
given,
m3 =(m1 +m2) , v3 = 2.3 m/s
So, using, m1v1 +m2v2 = m3v3,
we get, 2.4 x 1.3 + m2 x 4.2 = (2.4+m2) x 2.3
3.12 + m2 x 4.2 = 5.52 + 2.3xm2
1.9 m2 = 2.4
So, m2 = 1.26 Kg --> Answer
please be descriptive so i actually understand it. A 2.4 kg block slides along a frictionless...
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