Homework Answers
Answer 6: -34.653 kJ
answer 7: 284 kJ
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Hess's Law 6. Given the following data: C(graphite) C(diamond); AH -+1.897 k Coo(fullerene); AHo+2193 k) 60...
Using Hess's Law to Calculate a Standard Enthalpy of Formation On the Solution Calorimetry Lab Report...
Using Hess's Law to Calculate a Standard Enthalpy of Formation On the Solution Calorimetry Lab Report Form, vou will be asked to calculate a standard enthalpy of formation for magnesium oxide based on your experimental results. Below is an example of how to do this type of calculation. Calculate the standard enthalpy of formation of gaseous diborane (B2H6) using the following thermochemical equations: 4 B(s) + 3 O2(g)-> 2 B2O3(s) 2 H2(g) + O2(g) > 2 H20(0) B2H6(8) +3 O2(g)...
What is the standard Gibbs free energy for the transformation of diamond to graphite at 298 K? Cdiamond?Cgraphite Exp...
What is the standard Gibbs free energy for the transformation of diamond to graphite at 298 K? Cdiamond?Cgraphite Express your answer to three significant figures and include the appropriate units. Gibbs free energy is a measure of the spontaneity of a chemical reaction. It is the chemical potential for a reaction, which is minimized at equilibrium. It is defined as G=H?TS Elemental carbon usually exists in one of two forms: graphite or diamond. It is generally believed that diamonds last...
19. Calculate AH° for the conversion of graphite into diamond from the following thermochemical equations. C(s,...
19. Calculate AH° for the conversion of graphite into diamond from the following thermochemical equations. C(s, graphite) + O2(g) — C(s, diamond) + O2(g) CO2(g) AH° = -393.5 kJ + CO2(g) AH' = -395.9 kJ e uso -395.9 kJ +393.5 kJ -789.4 kJ +2.4 kJ -2.4 kJ
3. (25 pts) Buckminsterfullerene is a molecule with the formula C. (60 atoms of carbon held...
3. (25 pts) Buckminsterfullerene is a molecule with the formula C. (60 atoms of carbon held together by covalent bonds). It was manufactured in 1985 at Rice University. Given the following data: CO2(g) + C(s, graphite) + O2(8) AH,° = +393.5 kJ 60 CO2 (g) → Co (s) + 60 02(8) AH2° = +25937 kJ Write the balanced standard enthalpy equation for the formation of solid Coo law to determine the standard enthalpy (or heat) formation of solid Co. Buckminsterfullere
calculate delta H for the reaction C(diamond)=C(graphite) given the following data C(diamond)+O2(g)=CO2(g) deltaH=-395.45kJ C(graphite)+O2(g)=CO2(g) delta H=...
calculate delta H for the reaction C(diamond)=C(graphite) given the following data C(diamond)+O2(g)=CO2(g) deltaH=-395.45kJ C(graphite)+O2(g)=CO2(g) delta H= 393.5kJ deltaH=
The standard enthalpy change for the following reaction is -111 kJ at 298 K. C(s,graphite) +...
The standard enthalpy change for the following reaction is -111 kJ at 298 K. C(s,graphite) + 1/2 O2(g) --> CO(g) ΔH° = -111 kJ What is the standard enthalpy change for the reaction at 298 K? 2 CO(g) --> 2 C(s,graphite) + O2(g) Answer in kJ
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below:...
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below:...
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
Which of the following statements is/are correct? 1. ∆H° for the reaction C(diamond) + O2(g) →...
Which of the following statements is/are correct? 1. ∆H° for the reaction C(diamond) + O2(g) → CO2(g) is the enthalpy of combustion of diamond. 2. ∆H° for the reaction C(graphite) + 1/2 O2(g) → CO(g) is the standard enthalpy of formation (∆Hf) of CO(g). 3. ∆H° for the reaction C(graphite) → C(diamond) is the standard enthalpy of formation (∆Hf) of diamond. A. all B. 2 only C. 1 and 2 only D. 1 and 3 only E. 2 and 3...
PROBLEM-SOLVING CLASS ACTIVITY 11 Use Hess's Law to calculate the enthalpy of formation of CH2OH: C(graphite)...
PROBLEM-SOLVING CLASS ACTIVITY 11 Use Hess's Law to calculate the enthalpy of formation of CH2OH: C(graphite) + 2 H2(g) + 1026) → CH2OH(1) Given the following data: CH2OH() • 02(9) + CO2(g) + 2H2O(1) AH°: -726.4 kJ/mol C(graphite). O2(g) → CO2(9) AH' = -393.5 kJ/mol H2(g) + 40269) → H2O(1) AH = -285.8 kJ/mol
Using Hess's Law to Calculate a Standard Enthalpy of Formation On the Solution Calorimetry Lab Report Form, vou will be asked to calculate a standard enthalpy of formation for magnesium oxide based on your experimental results. Below is an example of how to do this type of calculation. Calculate the standard enthalpy of formation of gaseous diborane (B2H6) using the following thermochemical equations: 4 B(s) + 3 O2(g)-> 2 B2O3(s) 2 H2(g) + O2(g) > 2 H20(0) B2H6(8) +3 O2(g)...
19. Calculate AH° for the conversion of graphite into diamond from the following thermochemical equations. C(s, graphite) + O2(g) — C(s, diamond) + O2(g) CO2(g) AH° = -393.5 kJ + CO2(g) AH' = -395.9 kJ e uso -395.9 kJ +393.5 kJ -789.4 kJ +2.4 kJ -2.4 kJ
3. (25 pts) Buckminsterfullerene is a molecule with the formula C. (60 atoms of carbon held together by covalent bonds). It was manufactured in 1985 at Rice University. Given the following data: CO2(g) + C(s, graphite) + O2(8) AH,° = +393.5 kJ 60 CO2 (g) → Co (s) + 60 02(8) AH2° = +25937 kJ Write the balanced standard enthalpy equation for the formation of solid Coo law to determine the standard enthalpy (or heat) formation of solid Co. Buckminsterfullere
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
PROBLEM-SOLVING CLASS ACTIVITY 11 Use Hess's Law to calculate the enthalpy of formation of CH2OH: C(graphite) + 2 H2(g) + 1026) → CH2OH(1) Given the following data: CH2OH() • 02(9) + CO2(g) + 2H2O(1) AH°: -726.4 kJ/mol C(graphite). O2(g) → CO2(9) AH' = -393.5 kJ/mol H2(g) + 40269) → H2O(1) AH = -285.8 kJ/mol
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