Homework Answers
first write the both equations and then changes them i.e
reverse and multiplications to obtain final equation and then
calculate the delta H as follows
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3. (25 pts) Buckminsterfullerene is a molecule with the formula C. (60 atoms of carbon held...
Enter your answer in the provided box. Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, dia...
Enter your answer in the provided box. Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Determine A Hrxn for C(diamond) — Сgraphite) with equations from the following list: (1) C(diamond) + O2(g) + CO2(g) (2) 2 CO2(g) → 2 CO(g) + O2(8) (3) C(graphite) + O2(g) → CO2(g) (4) 2 CO(g) → C(graphite) + CO2(g) AH=-395.4 kJ...
Hess's Law 6. Given the following data: C(graphite) C(diamond); AH -+1.897 k Coo(fullerene); AHo+2193 k) 60...
Hess's Law 6. Given the following data: C(graphite) C(diamond); AH -+1.897 k Coo(fullerene); AHo+2193 k) 60 C(graphite) calculate the standard enthalpy of reaction for the conversion of buckminsterfullerene (Co) Into diamond: 1/60 Ceo (fullerene) C (diamond) 7. Given the following thermochemical data at 25°C and 1 atm pressure: O2(g) +2 B(s) B2O3(s), AHo-1264 k) O3(9) +2 B(s) calculate the standard enthalpy for the following reaction: B2O3(s), AHo=-1406 k) 2 O3(g) 3 O2(g) b
4. You are given the following information. C (graphite) + O2(g) — CO2 (g) CO(g) +...
4. You are given the following information. C (graphite) + O2(g) — CO2 (g) CO(g) + 02 (g) - CO2 (g) Determine the standard enthalpy change for the reaction: C (graphite) + / O2 (g) - CO (g) AH° = - 393.5 kJ AH° = - 283.0 kJ AHrxn = ?
please help 4. You are given the following information. C (graphite) + O2 (g) - CO2...
please help
4. You are given the following information. C (graphite) + O2 (g) - CO2 (g) CO(g) + 02 (9) - CO2 (g) Determine the standard enthalpy change for the reaction: C (graphite) + 02 (g) - CO(g) AH = - 393.5 kJ AH° = -283.0 kJ AHrxn = ?
Diamon and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes...
Diamon and graphite are two crystalline forms of
carbon. At 1 atm and 25°C, diamond changes to graphite so slowly
that the enthalpy change of the process must be obtained
indirectly. Determine delta H rxn for C(diamond) >
C(graphite)
with equations from the following list:
Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Determine AHxn for C(diamond)...
Calculate the standard enthalpy of formation of solid calcium carbonate (CaCO3) using the following thermochemical information:...
Calculate the standard enthalpy of formation of solid calcium
carbonate (CaCO3) using the following thermochemical
information:
Calculate the standard enthalpy of formation of solid calcium carbonate (CaCo3) using the following thermochemical information: 2 Cao(s) 2 Ca(s) O2(g) AH 1270.2 kJ C(s) O2 (g) CO2 (g) AH 393.5 kJ AH 178.3 kJ CaO(s) CO2 (g) CaCO3(s) kJ AH
7- (15 pts) Calculate the standard enthalpy of formation of CS2 (1) given that a. C(s)...
7- (15 pts) Calculate the standard enthalpy of formation of CS2 (1) given that a. C(s) + O2(g) + CO2(g) b. S(s) + O2(g) → SO2(e) C. CS2() + 302(g) → CO2(g) + ' 250 (6) AH° = -393.5 kJ/mol AH° = -296.4 kJ/mol AH° = -1073.6 kj/mol (the standard state of the element Sulfur is S(s))
e. -413.5 kJ = [71-52.7) + 3(-7-6 -25(15.) + -00- - 583.7 .180.7 17. The standard...
e. -413.5 kJ = [71-52.7) + 3(-7-6 -25(15.) + -00- - 583.7 .180.7 17. The standard enthalpy of combustion for naphthalene, C H , (s), is -5156.8 kJ mol-1. Using this data and the standard enthalpies of formation, AH : H2O(l) = -285.9 kJ mol-1; CO2 (g) = -393.5 kJ mol-1, calculate the standard enthalpy of formation of Co H, (s), in kJ mol-1. a. +78.2 kJ b. +935.9 kJ c. -1065.4 kJ d. +3619.7 kJ e. -10235.4 kJ
which of the following statements is/are true concerning a state function Using the standard enthalpies of...
which of the following statements is/are true concerning a
state function
Using the standard enthalpies of formation listed below, determine the standard enthalpy change for the following reaction: Fe2O3(s) + 3CO(g) ---> 2Fe(s) + 3C02() AH°-m AH" for Fe2O3(s) --824.2 kJ/mol AH® for CO(g) = -110.5 kJ/mol AH", for CO2(g) - -393.5 kJ/mol
Given the enthalpies of combustion of propane (C3Hg), carbon and hydrogen, C3H3(g) + 5 O2(g) +...
Given the enthalpies of combustion of propane (C3Hg), carbon and hydrogen, C3H3(g) + 5 O2(g) + 3 CO2(g) + 4 H20(1) AH° = -2219.9 kJ C(s) + O2(g) + CO2(8) AH° = -393.5 kJ 2 H2(g) + O2 + 2 H2O(1) AH° = -571.6 kJ Calculate the enthalpy of formation of propane. The reaction is shown below. 3 C(s) + 4H2(g) → C3H3(g)
Enter your answer in the provided box. Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Determine A Hrxn for C(diamond) — Сgraphite) with equations from the following list: (1) C(diamond) + O2(g) + CO2(g) (2) 2 CO2(g) → 2 CO(g) + O2(8) (3) C(graphite) + O2(g) → CO2(g) (4) 2 CO(g) → C(graphite) + CO2(g) AH=-395.4 kJ...
Hess's Law 6. Given the following data: C(graphite) C(diamond); AH -+1.897 k Coo(fullerene); AHo+2193 k) 60 C(graphite) calculate the standard enthalpy of reaction for the conversion of buckminsterfullerene (Co) Into diamond: 1/60 Ceo (fullerene) C (diamond) 7. Given the following thermochemical data at 25°C and 1 atm pressure: O2(g) +2 B(s) B2O3(s), AHo-1264 k) O3(9) +2 B(s) calculate the standard enthalpy for the following reaction: B2O3(s), AHo=-1406 k) 2 O3(g) 3 O2(g) b
4. You are given the following information. C (graphite) + O2(g) — CO2 (g) CO(g) + 02 (g) - CO2 (g) Determine the standard enthalpy change for the reaction: C (graphite) + / O2 (g) - CO (g) AH° = - 393.5 kJ AH° = - 283.0 kJ AHrxn = ?
please help
4. You are given the following information. C (graphite) + O2 (g) - CO2 (g) CO(g) + 02 (9) - CO2 (g) Determine the standard enthalpy change for the reaction: C (graphite) + 02 (g) - CO(g) AH = - 393.5 kJ AH° = -283.0 kJ AHrxn = ?
Diamon and graphite are two crystalline forms of
carbon. At 1 atm and 25°C, diamond changes to graphite so slowly
that the enthalpy change of the process must be obtained
indirectly. Determine delta H rxn for C(diamond) >
C(graphite)
with equations from the following list:
Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Determine AHxn for C(diamond)...
Calculate the standard enthalpy of formation of solid calcium
carbonate (CaCO3) using the following thermochemical
information:
Calculate the standard enthalpy of formation of solid calcium carbonate (CaCo3) using the following thermochemical information: 2 Cao(s) 2 Ca(s) O2(g) AH 1270.2 kJ C(s) O2 (g) CO2 (g) AH 393.5 kJ AH 178.3 kJ CaO(s) CO2 (g) CaCO3(s) kJ AH
7- (15 pts) Calculate the standard enthalpy of formation of CS2 (1) given that a. C(s) + O2(g) + CO2(g) b. S(s) + O2(g) → SO2(e) C. CS2() + 302(g) → CO2(g) + ' 250 (6) AH° = -393.5 kJ/mol AH° = -296.4 kJ/mol AH° = -1073.6 kj/mol (the standard state of the element Sulfur is S(s))
e. -413.5 kJ = [71-52.7) + 3(-7-6 -25(15.) + -00- - 583.7 .180.7 17. The standard enthalpy of combustion for naphthalene, C H , (s), is -5156.8 kJ mol-1. Using this data and the standard enthalpies of formation, AH : H2O(l) = -285.9 kJ mol-1; CO2 (g) = -393.5 kJ mol-1, calculate the standard enthalpy of formation of Co H, (s), in kJ mol-1. a. +78.2 kJ b. +935.9 kJ c. -1065.4 kJ d. +3619.7 kJ e. -10235.4 kJ
which of the following statements is/are true concerning a
state function
Using the standard enthalpies of formation listed below, determine the standard enthalpy change for the following reaction: Fe2O3(s) + 3CO(g) ---> 2Fe(s) + 3C02() AH°-m AH" for Fe2O3(s) --824.2 kJ/mol AH® for CO(g) = -110.5 kJ/mol AH", for CO2(g) - -393.5 kJ/mol
Given the enthalpies of combustion of propane (C3Hg), carbon and hydrogen, C3H3(g) + 5 O2(g) + 3 CO2(g) + 4 H20(1) AH° = -2219.9 kJ C(s) + O2(g) + CO2(8) AH° = -393.5 kJ 2 H2(g) + O2 + 2 H2O(1) AH° = -571.6 kJ Calculate the enthalpy of formation of propane. The reaction is shown below. 3 C(s) + 4H2(g) → C3H3(g)
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