4. You are given the following information. C (graphite) + O2(g) — CO2 (g) CO(g) +...
please help 4. You are given the following information. C (graphite) + O2 (g) - CO2 (g) CO(g) + 02 (9) - CO2 (g) Determine the standard enthalpy change for the reaction: C (graphite) + 02 (g) - CO(g) AH = - 393.5 kJ AH° = -283.0 kJ AHrxn = ?
From the following data, C(graphite) + O2(g) → CO2(g) AHrxn = -393.5 kJ/mol H2(g) + O2(g) → H200) AH"rxn = -285.8 kJ/mol 2C2H6(g) + 702(g) -> 4CO2(g) + 6H2O(l) Arxn=-3119.6 kJ/mol Calculate the enthalpy change for the reaction: 2 C(graphite) + 3H2(g) + C2H668)
Based on the following equations: 2 CO2(g) + O2(g) + 2 CO (g) AH- +566.0kJ 2(graphite) + O2(g) + 2 CO (5) AH = -221.0 kJ Determine the enthalpy change (AH) for the following reaction: C(graphite) + O2 (8) CO2(g)
e. -1135 Given the following reactions: CaCO3 (s)-> Cao (s) + CO2 (g) C (s, graphite) + O2 (g)-> Co2 (g) AH-393.5 kJ the enthalpy of the reaction CaCO3 (s) -> CaO (s) + C (s, graphite) + O2 (g) ΔH = 178.1 kJ is kJ Select one: 4 a. 7.01 x 10 b. 571.6 ) c. 215.4 d. -215.4 ie. -571.6 Check Given the data in the table below, AH for the reaction
carbon. Determine the AHrxn for C (diamond) → C (graphite), using the following thermochemical equations: a) C (diamond) + 02 (9) → CO2 (9) AH = -395.4 kJ b) CO (9) + 12 02 (9) → CO2 (9) AH = -283.0 kJ c) C (graphite) + CO2 (9) ► 2 CO (9) AH = +172.5 kJ
Enter your answer in the provided box From the following data, C(graphite) + O2(0)+ CO2(g) An° . =-393.5 kJ/mol rxn Hy(@) +0,6) H200 AH =-285.8 kJ/mol rxn 2C2H6(8) + 1026) →40026) + 6H20(1) AH =-3119.6 kJ/mol rxn calculate the enthalpy change for the reaction below: 2 C(graphite) + 3H2(g) → CH()
[32] The enthalpy of reaction for [6] enthalpy of reaction for the combustion of C to CO, is-393.5 kJ/mol C, and the enthalpy for the combustion of CO to CO, is-283.0 kJ/mol CO: (i) C(s) + O2(g) + CO2(e) AH -393.5 kJ CO(g) + O2(g) + CO2(g) AH -283.0 kJ Using these data, calculate the enthalpy for the combustion of C to CO. (iii) C(s) + O2(g) - CO(g) AH-?
7. The enthalpy of combustion of C to CO2 is –393.5 kJ/mol C, and the enthalpy of combustion of Co to CO2 is -283.0 kJ/mol CO: C(s) + O2(g) + CO2(g) AH = -393.5 kJ CO(g) + 102(9) CO2(g) AH = -283.0 kJ Using these data, calculate the enthalpy of combustion of C to CO: C(s) + O2(g) → CO(g) AH = ? Answer: -110.5 kJ
Please explain Data: C(graphite) + O2(g) => CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) => H2O(1) AH = -285.8 kJ CH3OH(1) + 3/202(9) A CO2(g) + 2H20(1) AH = -726.4 kJ Using the data above, calculate the enthalpy change for the reaction below. Reaction: C(graphite) + 2H2(g) + 1/2O2(g) => CH3OH(1) A. +238.7 kJ B.-238.7 kJ C. +548.3 kJ D.-548.3 kJ E. +904.5 kJ
Determine the enthalpy change for C(graphite) + O2(g) → CO2(g); AH= ? using the following three thermochemical equations, which will be referred to as reactions (A), (B), and (C). (A) Sro(s) + CO2(g) → SCO3(s);AH = -234 kJ (B) 2Sro(s) → 25r(s) + O2(g); AH= 1184 kJ (C) 2SrCO3(s) — 25r(s) + 2C(graphite) + 302(g); AH= 2440 kJ The value for AH = List what action you performed on each equation to achieve your goal. Equation (A) was Equation (B)...