Homework Answers
Therefore
the answer is ,the change in enthalpy is -84.6KJ/mol
According to Hess's Law of Constant Heat Summation,it is stated that for a given chemical process,the net heat-change will be the same whether the process occurs in one or in several steps
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Enter your answer in the provided box From the following data, C(graphite) + O2(0)+ CO2(g) An°...
From the following data, C(graphite) + O2(g) → CO2(g) AHrxn = -393.5 kJ/mol H2(g) + O2(g)...
From the following data, C(graphite) + O2(g) → CO2(g) AHrxn = -393.5 kJ/mol H2(g) + O2(g) → H200) AH"rxn = -285.8 kJ/mol 2C2H6(g) + 702(g) -> 4CO2(g) + 6H2O(l) Arxn=-3119.6 kJ/mol Calculate the enthalpy change for the reaction: 2 C(graphite) + 3H2(g) + C2H668)
1 out of 10 attemp Enter your ans wer in the provided box Diamond and graphite...
1 out of 10 attemp Enter your ans wer in the provided box Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. DetermineA for rxn (diamond)- → C (graphite) C with equations from the following list: (1) Cdia (2) 2CO2(g)→2CO(g ) + O2(g) (3) C(graphite) +02(g)→CO2(g) (4) 2C0(g)→C(graphite) + CO2(g) AH AH-566.0 kJ AH--393.5 kJ AH--172.5kJ =-395.4 kJ...
Enter your answer in the provided box Use the following data to calculate ΔΗο for CS20:...
Enter your answer in the provided box Use the following data to calculate ΔΗο for CS20: C(graphite)+ O2(8)-Co2() S(rhombic) +02(g) → SO2(g) CS2(0) + 302(8) CO2(8) + 2S02(3) o AH =-393.5 kJ/rnol rxn AH296.4 kJ/mol rxn AHorn =-1073.6 kJ/mol 0
Enter your answer in the provided box. Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, dia...
Enter your answer in the provided box. Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Determine A Hrxn for C(diamond) — Сgraphite) with equations from the following list: (1) C(diamond) + O2(g) + CO2(g) (2) 2 CO2(g) → 2 CO(g) + O2(8) (3) C(graphite) + O2(g) → CO2(g) (4) 2 CO(g) → C(graphite) + CO2(g) AH=-395.4 kJ...
Please explain Data: C(graphite) + O2(g) => CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) =>...
Please explain
Data: C(graphite) + O2(g) => CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) => H2O(1) AH = -285.8 kJ CH3OH(1) + 3/202(9) A CO2(g) + 2H20(1) AH = -726.4 kJ Using the data above, calculate the enthalpy change for the reaction below. Reaction: C(graphite) + 2H2(g) + 1/2O2(g) => CH3OH(1) A. +238.7 kJ B.-238.7 kJ C. +548.3 kJ D.-548.3 kJ E. +904.5 kJ
4. You are given the following information. C (graphite) + O2(g) — CO2 (g) CO(g) +...
4. You are given the following information. C (graphite) + O2(g) — CO2 (g) CO(g) + 02 (g) - CO2 (g) Determine the standard enthalpy change for the reaction: C (graphite) + / O2 (g) - CO (g) AH° = - 393.5 kJ AH° = - 283.0 kJ AHrxn = ?
3 attempts left Check my work Enter your answer in the provided box. Calculate AG for...
3 attempts left Check my work Enter your answer in the provided box. Calculate AG for the reaction at 25°C. 2C6H61) + 1502(8) 12C028) + 6H20(1) agº = kJ AH° (kJ/mol Agº (kJ/mol) sº (J/K mol) 5.69 2.4 Substance C(graphite) C(diamond) CO(g) CO2(g) CO2(aq) C0,- (aq) O(g) O2(8) O3(aq) O3(8) H20(1) CH 1.90 -110.5 -393.5 -412.9 -676.3 249.4 2.87 --137.3 -394.4 -386.2 --528.1 230.1 0 16.3 163.4 -237.2 124.5 197.9 213.6 121.3 -53.1 160.95 205.0 110.88 237.6 -12.09 142.2 -285.8...
please help 4. You are given the following information. C (graphite) + O2 (g) - CO2...
please help
4. You are given the following information. C (graphite) + O2 (g) - CO2 (g) CO(g) + 02 (9) - CO2 (g) Determine the standard enthalpy change for the reaction: C (graphite) + 02 (g) - CO(g) AH = - 393.5 kJ AH° = -283.0 kJ AHrxn = ?
9.Enter your answer in the provided box. S(rhombic) + O2(g) → SO2(g) ΔHo rxn= −296.06 kJ/mol...
9.Enter your answer in the provided box. S(rhombic) + O2(g) → SO2(g) ΔHo rxn= −296.06 kJ/mol S(monoclinic) + O2(g) → SO2(g) ΔHo rxn= −296.36 kJ/mol calculate the enthalpy change for the transformation S(rhombic) → S(monoclinic) (Monoclinic and rhombic are different allotropic forms of elemental sulfur.) _______kJ/mol 10. Enter your answer in the provided box Use the following data to calculate ΔHo/f for CS2(l): C(graphite) + O2(g) → CO2(g) ΔHo rxn= −393.5 kJ/mol S(rhombic) + O2(g) → SO2(g) ΔHo rxn=...
PROBLEM-SOLVING CLASS ACTIVITY 11 Use Hess's Law to calculate the enthalpy of formation of CH2OH: C(graphite)...
PROBLEM-SOLVING CLASS ACTIVITY 11 Use Hess's Law to calculate the enthalpy of formation of CH2OH: C(graphite) + 2 H2(g) + 1026) → CH2OH(1) Given the following data: CH2OH() • 02(9) + CO2(g) + 2H2O(1) AH°: -726.4 kJ/mol C(graphite). O2(g) → CO2(9) AH' = -393.5 kJ/mol H2(g) + 40269) → H2O(1) AH = -285.8 kJ/mol
From the following data, C(graphite) + O2(g) → CO2(g) AHrxn = -393.5 kJ/mol H2(g) + O2(g) → H200) AH"rxn = -285.8 kJ/mol 2C2H6(g) + 702(g) -> 4CO2(g) + 6H2O(l) Arxn=-3119.6 kJ/mol Calculate the enthalpy change for the reaction: 2 C(graphite) + 3H2(g) + C2H668)
1 out of 10 attemp Enter your ans wer in the provided box Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. DetermineA for rxn (diamond)- → C (graphite) C with equations from the following list: (1) Cdia (2) 2CO2(g)→2CO(g ) + O2(g) (3) C(graphite) +02(g)→CO2(g) (4) 2C0(g)→C(graphite) + CO2(g) AH AH-566.0 kJ AH--393.5 kJ AH--172.5kJ =-395.4 kJ...
Enter your answer in the provided box Use the following data to calculate ΔΗο for CS20: C(graphite)+ O2(8)-Co2() S(rhombic) +02(g) → SO2(g) CS2(0) + 302(8) CO2(8) + 2S02(3) o AH =-393.5 kJ/rnol rxn AH296.4 kJ/mol rxn AHorn =-1073.6 kJ/mol 0
Enter your answer in the provided box. Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Determine A Hrxn for C(diamond) — Сgraphite) with equations from the following list: (1) C(diamond) + O2(g) + CO2(g) (2) 2 CO2(g) → 2 CO(g) + O2(8) (3) C(graphite) + O2(g) → CO2(g) (4) 2 CO(g) → C(graphite) + CO2(g) AH=-395.4 kJ...
Please explain
Data: C(graphite) + O2(g) => CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) => H2O(1) AH = -285.8 kJ CH3OH(1) + 3/202(9) A CO2(g) + 2H20(1) AH = -726.4 kJ Using the data above, calculate the enthalpy change for the reaction below. Reaction: C(graphite) + 2H2(g) + 1/2O2(g) => CH3OH(1) A. +238.7 kJ B.-238.7 kJ C. +548.3 kJ D.-548.3 kJ E. +904.5 kJ
4. You are given the following information. C (graphite) + O2(g) — CO2 (g) CO(g) + 02 (g) - CO2 (g) Determine the standard enthalpy change for the reaction: C (graphite) + / O2 (g) - CO (g) AH° = - 393.5 kJ AH° = - 283.0 kJ AHrxn = ?
3 attempts left Check my work Enter your answer in the provided box. Calculate AG for the reaction at 25°C. 2C6H61) + 1502(8) 12C028) + 6H20(1) agº = kJ AH° (kJ/mol Agº (kJ/mol) sº (J/K mol) 5.69 2.4 Substance C(graphite) C(diamond) CO(g) CO2(g) CO2(aq) C0,- (aq) O(g) O2(8) O3(aq) O3(8) H20(1) CH 1.90 -110.5 -393.5 -412.9 -676.3 249.4 2.87 --137.3 -394.4 -386.2 --528.1 230.1 0 16.3 163.4 -237.2 124.5 197.9 213.6 121.3 -53.1 160.95 205.0 110.88 237.6 -12.09 142.2 -285.8...
please help
4. You are given the following information. C (graphite) + O2 (g) - CO2 (g) CO(g) + 02 (9) - CO2 (g) Determine the standard enthalpy change for the reaction: C (graphite) + 02 (g) - CO(g) AH = - 393.5 kJ AH° = -283.0 kJ AHrxn = ?
PROBLEM-SOLVING CLASS ACTIVITY 11 Use Hess's Law to calculate the enthalpy of formation of CH2OH: C(graphite) + 2 H2(g) + 1026) → CH2OH(1) Given the following data: CH2OH() • 02(9) + CO2(g) + 2H2O(1) AH°: -726.4 kJ/mol C(graphite). O2(g) → CO2(9) AH' = -393.5 kJ/mol H2(g) + 40269) → H2O(1) AH = -285.8 kJ/mol
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