Answer: ∆G° = -6307.23 KJ/mol
explanation:
Now ,
we know that,
∆G° = ∆H° - T∆S°
= -6767.8 kJ -( 298 K * -1545.54 j/mol)
= -6767.8 KJ/mol + 460570.92 J/mol
=-6767.8 KJ/mol + 460.57092 KJ/mol
∆H° = -6307 KJ/mol
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3 attempts left Check my work Enter your answer in the provided box. Calculate AG for...
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