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3 attempts left Check my work Enter your answer in the provided box. Calculate AG for the reaction at 25°C. 2C6H61) + 1502(8)
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Answer #1

Answer: ∆G° = -6307.23 KJ/mol

explanation:

We have, 2 G H6 (4) + 15 02 (6) 12 CO₂ (g) + 6H₂O (1) AH = AH brodeeds - Ato neautant = 12 Ati CO₂ + 6 AH 40 - [2A HO GHG + 1Now ,

we know that,

∆G° = ∆H° - T∆S°

= -6767.8 kJ -( 298 K * -1545.54 j/mol)

= -6767.8 KJ/mol + 460570.92 J/mol

=-6767.8 KJ/mol + 460.57092 KJ/mol

∆H° = -6307 KJ/mol

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