Question

Calculate AG for the following reaction at 25°C. 2 Ca(s) + O2(g) → 2 Ca(s) (J/K mol) Substance AH (kJ/mol AG (kJ/mol) Ca(s) C
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Answer #1

2 Ca(s) + O2(g) --------------- 2 CaO(s)

\DeltaGo of Ca(s) = 0.00 KJ

\DeltaGo of O2(g) = 0.00 KJ

\DeltaGo of CaO(s) = - 604.2 KJ

\DeltaGo = 2x \Delta Go of CaO - [ 2 x\DeltaGo of Ca + \Delta Go of O2]

\DeltaGo = 2 x ( - 604.2) - [ 2 x 0.00 + 0.00]

\DeltaGo = - 1208.4 KJ

(Or)

\DeltaHo = 2x \Delta Ho of CaO - [ 2 x\DeltaH of Ca + \Delta Ho of O2]

\DeltaHo = 2 x ( - 635.6) - [ 2 x 0.0 + 0.0]

\DeltaHo = - 1271.2 KJ

\DeltaSo = 2x \Delta So of CaO - [ 2 x\DeltaS of Ca + \Delta So of O2]

\DeltaSo = 2 x 39.8 - [ 2 x 41.6 + 205.0 ]

\DeltaSo = - 208.6 J

T= 25C = 25 + 273 = 298 K

\DeltaG0 = \Delta H0 - T \Delta So

\DeltaG0 = - 1271.2 - ( 298 x ( - 0.2086)]

\DeltaG0 = - 1209.0 KJ

The small differrence is possible depend on given values. ( the difference is 0.6)

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