2 Ca(s) + O2(g) --------------- 2 CaO(s)
Go of Ca(s) = 0.00 KJ
Go of O2(g) = 0.00 KJ
Go of CaO(s) = - 604.2 KJ
Go = 2x Go of CaO - [ 2 xGo of Ca + Go of O2]
Go = 2 x ( - 604.2) - [ 2 x 0.00 + 0.00]
Go = - 1208.4 KJ
(Or)
Ho = 2x Ho of CaO - [ 2 xH of Ca + Ho of O2]
Ho = 2 x ( - 635.6) - [ 2 x 0.0 + 0.0]
Ho = - 1271.2 KJ
So = 2x So of CaO - [ 2 xS of Ca + So of O2]
So = 2 x 39.8 - [ 2 x 41.6 + 205.0 ]
So = - 208.6 J
T= 25C = 25 + 273 = 298 K
G0 = H0 - T So
G0 = - 1271.2 - ( 298 x ( - 0.2086)]
G0 = - 1209.0 KJ
The small differrence is possible depend on given values. ( the difference is 0.6)
Calculate AG for the following reaction at 25°C. 2 Ca(s) + O2(g) → 2 Ca(s) (J/K...
3 attempts left Check my work Enter your answer in the provided box. Calculate AG for the reaction at 25°C. 2C6H61) + 1502(8) 12C028) + 6H20(1) agº = kJ AH° (kJ/mol Agº (kJ/mol) sº (J/K mol) 5.69 2.4 Substance C(graphite) C(diamond) CO(g) CO2(g) CO2(aq) C0,- (aq) O(g) O2(8) O3(aq) O3(8) H20(1) CH 1.90 -110.5 -393.5 -412.9 -676.3 249.4 2.87 --137.3 -394.4 -386.2 --528.1 230.1 0 16.3 163.4 -237.2 124.5 197.9 213.6 121.3 -53.1 160.95 205.0 110.88 237.6 -12.09 142.2 -285.8...
Information from the appendix is attached: 5. (20 pts) Consider the following reaction OF2(g) + H2O(g) ---> 2 HF(g) + O2(g) AH (kJ/mole) = -318 kJ/mole (a) Using this information along with data in the appendix of your textbook, calculate AH (OF, (g)) in kJ/mole at 25°C. (b) If 15.0 g of OF2(g) and 10.0 g of H2Og) react, how much heat, expressed in kJ is released? Hint: First calculate the limiting reagent. 6.(20 pts) Consider two Styrofoam coffee cups....
Thermodynamic Quantities for Selected Substances at 298.15K (25°C) Substance AHºt (kJ/mol) AG°f (kJ/mol) SI/K-mol) Caldum Ca(s) CaCl2 (s) Ca2+ (aq) 0 - 795.8 41.4 104.6 - 748.1 226.7 209.2 200.8 Chlorine Cl2 (8) Cl- (aq) 0 - 167.2 0 -131.2 222.96 56.5 Oxygen 02 (8) H20 (1) 0 0 -237.13 205.0 69.91 -285.83 Phosphorus P2 (8) PC13 (8) POCl3 (8) 144.3 -288.1 -542.2 103.7 -269.6 -502.5 218.1 311.7 325 Sulfur S (s, rhombic) 902(g) 9038) 0 -269.9 -395.2 0 -300.4...
c is the reaction: Ca(s) + 2 H20(1) Ca(OH)2(aq) + 2H2(8) -285.83 -1002.82 AH °(kJ/mol) S°(J/K) mol 41.59 69.95 -74.5 130.7 AH° = -431.16 AS° = 5.41 AG° = -432.77 enthalpy favored Oneither enthalpy and entropy favored O entropy favored O both enthalpy and entropy favored Submit
b Consider the reaction: Ca(s) +2 H2001) + Ca(OH)2(aq) +2H2(g) -285.83 -1002.82 AH" (kJ/mol) S°(J/K) mol 41.59 69.95 -74.5 130.7 Is the reaction spontaneous at 298 K? AH° = -431.16 AS° = 5.41 AG° = -432.77 O Yes O No Submit Submit Answer Retry Entire Group 9 more group attempts remaining
Calculate AG and K, at 25 °C for the reaction 2 CO(g) + O2(g) → 2 CO2(g) Is the reaction product-favored or reactant-favored under standard conditions? Thermodynamic Data: Species G (kJ/mol) CO(g)-137.17 CO2(g) -394.36 kJ/mol product-favored reactant-favored
Calculate AG and K at 25°C for the reactions. a. 7H,0 + 2 Cr3+ + 3Cl2 Cr2O72- +6C1° +14H+ Eden 0.03 V AG" KJ K= b. Cu2+ (aq) + Ca(s) = Ca2+ (aq) + Cu(s) €° = 3.10 V AG" kJ K= c. Cl2(9) +2 Br(aq) + Br2(g) + 2 C1-(aq) ' = 0.27 V AG" kJ K = d. 3H2O(1) + 5104- (aq) + 2 Mn²+ (aq) = 5103 - (aq) + 2 MnO4 (aq) + 6H+ (aq) =...
Consider the following cell reaction at 18°C: Ca(e)+Cu+ (aq) + Ca2+ (aq) + Cu() Calculate the standard cell potential of this cell from the standard electrode potentials, and from this, obtain AG" for the cell reaction. Calculate AF. Use these values of AN and AG to obtain AS for the cell reaction. Ca²+ (aq) +20 + Ca() --2.76 V Cu? (g) +20 + Cu(s) - 0.84 V AH;(O.*()) -- 542.8 kJ/mol AH;(Out (as)) - 64.8 kJ/mol V AG- AH- kJ...
Use the data found in the Thermodynamic Values link under Reference Materials to calculate ΔHo (KJ), ΔSo (J/K) and ΔGo(KJ) and ΔGo from the equation ΔGo ≈ ΔHo - TΔSo at 25.0 oC for 1. C2H5OH (g) → C2H4 (g) + H2O (l) 2. 2 C4H10 (l) + ___ O2 (g) → ___ CO2 (g) + ___ H2O (l) (Do not change a coefficient that is shown) 3. 2 C4H10 (g) + ___ O2 (g) → ___ CO2 (g) + ___ H2O (l) (Do not change a coefficient that...
Use the data found in the Thermodynamic Values link under Reference Materials to calculate ΔHo (KJ), ΔSo (J/K) and ΔGo(KJ) and ΔGo from the equation ΔGo ≈ ΔHo - TΔSo at 25.0 oC for 1. 1 C2H5OH(g) + ___ O2 (g) → ___ CO2 (g) + ___ H2O (g) (Do not change a coefficient that is shown) 2. 2 C4H10 (l) + ___ O2 (g) → ___ CO2 (g) + ___ H2O (g) (Do not change a coefficient that is shown) 3. C2H5OH (l) → C2H4 (g) + H2O (g) ...