Information from the appendix is attached: 5. (20 pts) Consider the following reaction OF2(g) + H2O(g)...
5. (20 pts) Consider the following reaction OF2(g) + H2O(g) ---> 2 HF(g) + O2(g) AH.(kJ/mole) -318 kJ/mole (a) Using this information along with data in the appendix of your textbook, calculate AH;(OF,(8)) in kJ/mole at 25°C. (b) If 15.0 g of OF2(g) and 10.0 g of H2Og) react, how much heat, expressed in kJ is released? Hint: First calculate the limiting reagent. 6.(20 pts) Consider two Styrofoam coffee cups. If cup #1 contains 102.0 mL of water at 81.8°C...
5. (20 pts) Consider the following reaction OF2(g) + H2O(g) ---> 2 HF(g) + O2(g) AH.(kJ/mole)=-318 kJ/mole (a) Using this information along with data in the appendix of your textbook, calculate AH (OF,(g)) in kJ/mole at 25°C. (b) If 15.0 g of OF2(g) and 10.0 g of H2Og) react, how much heat, expressed in kJ is released? Hint: First calculate the limiting reagent.
5. (20 pts) Consider the following reaction OF:(g)+ H20(g) (a) Using this information along with data in the appendix of your textbook, calculate AH(OF, (g)) in kJ/mole at 25 C. (b) If 15.0 g of OF (g) and 10.0 g of H2Og) react, how much heat, expressed in kJ is released? Hint: First calculate the limiting reagent. 2 HF(g) + O(g) AH (kJ/mole)--318 kJ/mole Consider two Styrofoam coffee cups. If cup # 1 contains 102.0 mL of water at 81.8...
Using enthalpies of formation (Appendix C), calculate ΔH ° for the following reaction at 25°C. Also calculate ΔS ° for this reaction from standard entropies at 25°C. Use these values to calculate ΔG ° for the reaction at this temperature. COCl2(g) + H2O(l ) h CO2(g) + 2HCl(g). Appendix C Thermodynamic Quantities for Substances and Ions at 25°C Substance or lon AH; (kW/mol) 0 AG: (kJ/mol) 0 S° (J/mol-K) 20.87 ΔΗ, (kJ/mol) -946.3 - 33422 AG; {kj/mol) --859,3 -2793 (J/mol-K)...
Consider the reaction 2 CO2(g) +5 H2(e) C H2(e) + 4H2O(g) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K ANSWER: Submit Answer Retry Entire Group more group attempts remaining AH,(kJ/mol) AG® (kJ/mol) Sº (J/mol K) -238.7 -116.0 126.8 219.0 -363.0 249.0 135.1 -166.3 -110.0 -351.0 125.0 209.2 68.2 - 129.0 202.0 226.7 200.9 52.3 - 166.0 -53.0 -277.7 219.6 250.0 242.0 160.7 -13.0 -235.1 282.7 Carbon CH3OH (1) H2CO...
2. Calculate AH (expressed in kJ/mol) for the following reaction based on the thermochemical information given: Na +Crce → NaCl AH ? Nas) + 2Cl2(g) → Nap + Cle AH = 230 kJ/mol Nag) + Cl → Na(+ Cl® AH = 147 kJ/mol Na(s) + Cl2(e) → NaCl) AH = -411 kJ/mol 3. Consider the reaction: 2HCl) + Ba(OH)2(aq) → BaCl(aq) + 2 H200 AH--118 kJ/mol a. Calculate the heat produced when 700.0 mL of 0.500 M HCl is mixed...
Calculate the in kJ/mole given that the following reaction has a = -1219.26 kJ/mol 2 ClF3(g) + 2 NH3(g) ----- > N2(g) + 6 HF(g) + Cl2(g) Use data in appendix III (b) The military uses FRH’s (Flameless ration heaters) to heat MRE’s (meals ready to eat). (Heat of formation of Mg( OH)2(Aqua) = -926.8 kJ/mole One of the reactions used in an FRH is Mg(s) + 2 H2O(l) ------ > Mg(OH)2(aq) + H2(g) Using data in Appendix III...
(7 pts.) Calculate the heat absorbed when 4.20 g of H2 are produced according to the following equation. CH3OH (g) → CO(g) + 2 H2(g) AH = 90.2 kJ (7 pts.) When one adds 1.475 kJ of heat energy to a sample of gold, the temperature goes from 12.5 °C to 84.6 °C. Calculate the mass of the sample of gold. Gold has a specific heat capacity of 0.129 J/g.°C. (6 pts.) 10. Write the thermochemical equation for the standard...
17.51 Calculate the entropy change for the following processes. (a) 1.00 mol H,O(s) melts at 0 °C. AH = 6.01 kJ/mol. (b) 2.00 mol CH.() vaporizes at 80.0 °C. AH vap = 30.7 kJ/mol. 17.52 - Calculate the entropy change for the following processes. (a) 2.00 mol NH3(e) vaporizes at -33.0 °C. AHvap = 23.35 kJ/mol. (b) 1.00 mol C,H,OH(s) melts at -114 °C. AHjus = 5.0 kJ/mol. 17.53 Use data from Appendix G to calculate the standard entropy change...
#4.(25pts) Consider the reaction AH (kJ/mole) 5 CO2(g) + SizN() ----> 3 SiO(g) + 2 N2O(s) + 5 CO(g) AH = 2023.75 kJ/mole (1) Use the above information as well as heat of formation data in the appendix of your textbook to calculate AH (Si,N.(s)) in kJ/mole. Additional information: AH (SiO(g)) = 1.94 x 109 kJ/mole 6) How many kJ of heat are absorbed when 1.2 lbs of Si N.(s) react according to the above equation? 1 lb = 453.6...