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c is the reaction: Ca(s) + 2 H20(1) Ca(OH)2(aq) + 2H2(8) -285.83 -1002.82 AH °(kJ/mol) S°(J/K)...
b Consider the reaction: Ca(s) +2 H2001) + Ca(OH)2(aq) +2H2(g) -285.83 -1002.82 AH" (kJ/mol) S°(J/K) mol...
b Consider the reaction: Ca(s) +2 H2001) + Ca(OH)2(aq) +2H2(g) -285.83 -1002.82 AH" (kJ/mol) S°(J/K) mol 41.59 69.95 -74.5 130.7 Is the reaction spontaneous at 298 K? AH° = -431.16 AS° = 5.41 AG° = -432.77 O Yes O No Submit Submit Answer Retry Entire Group 9 more group attempts remaining
This question has multiple parts. Work all the parts to get the most points. a Consider...
This question has multiple parts. Work all the parts to get the most points. a Consider the reaction: Ca(s) +2 H20(1) - Ca(OH)2(aq) +2H2(g) AH:º(kJ/mol -285.83 -1002.82 S°(J/K) mol 41.59 69.95 -74.5 130.7 What are the values of AH°, ASand AG° AH° kJ/mol AS° = J/K.mol AG° = kJ/mol Submit Submit Answer Try Another Version 6 item attempts remaining
Consider the reaction Ca(OH)2(aq) + 2HCl(aq)CaCl2(s) + 2H2O(l) for which H° = -30.20 kJ and S°...
Consider the reaction Ca(OH)2(aq) + 2HCl(aq)CaCl2(s) + 2H2O(l) for which H° = -30.20 kJ and S° = 205.9 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 1.934 moles of Ca(OH)2(aq) react under standard conditions at 298.15 K. Suniverse = ----------J/K (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is...
For the reaction Ca(OH)2(aq) + 2HCl(aq) +CaCl2(s) + 2H2O(1) AH° = -30.2 kJ and AS° =...
For the reaction Ca(OH)2(aq) + 2HCl(aq) +CaCl2(s) + 2H2O(1) AH° = -30.2 kJ and AS° = 205.9 J/K The maximum amount of work that could be done when 1.91 moles of Ca(OH)2(aq) react at 291 K, 1 atm is kJ. Assume that AH° and AS° are independent of temperature. Submit Answer Retry Entire Group 3 more group attempts remaining
Equations AS-re/T, AS system= ES® (products) - ES (reactants); AS univ=AS sys+AS sur; AGⓇ-AH- AGG products...
Equations AS-re/T, AS system= ES® (products) - ES (reactants); AS univ=AS sys+AS sur; AGⓇ-AH- AGG products - Gractants; AGⓇ--RT In K TAS: Constants SJ/mol K): Na(s)=51.21, H20(1=69.95, NaOH(aq)-48.1, H2(g)=130.7 AHºr kJ/mol : Na(s)=0, H2O(I=-285.83, NaOH(aq)=-469.15, H2(g)=0 1) For the reaction: Na(s) + H2O(l) → NaOH(aq) + H2(g) at 298K a) Calculate AHºrn b) Calculate AS system c) Calculate AG® d) Explain why the reaction is favored by enthalpy, entropy favored, both or neither? e) Which direction does the equilibrium shift...
Calculate AG for the following reaction at 25°C. 2 Ca(s) + O2(g) → 2 Ca(s) (J/K...
Calculate AG for the following reaction at 25°C. 2 Ca(s) + O2(g) → 2 Ca(s) (J/K mol) Substance AH (kJ/mol AG (kJ/mol) Ca(s) Ca2+(aq) CaO(s) Ca(OH)2(5) CaF2(5) CaCl(s) O(g) 028) O3(aq) Oz(8) -542.96 -635.6 -986.6 -1,214.6 -794.96 249.4 -553.0 -604.2 -896.8 -1,161.9 -750.19 230.1 41.6 -55.2 39.8 83.4 68.87 113.8 160.95 205.0 110.88 237.6 -12.09 142.2 16.3 163.4
help with this please Ca(OH)2(aq) + 2 HCl(aq) +CaCl2(8) + 2 H2O(1) Using the standard thermodynamic...
help with this please
Ca(OH)2(aq) + 2 HCl(aq) +CaCl2(8) + 2 H2O(1) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K ANSWER: N2(g) + O2(g) +2NO(g) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K ANSWER: 2CO(g) + O2(g) +2002(9) - der e en manos de 20, ali ne more than one so mi dicogna undan Using standard thermodynamic data...
8. Calcium carbide (CaC2) reacts with water to form acetylene (C2H2) and Ca(OH)2. From the following...
8. Calcium carbide (CaC2) reacts with water to form acetylene (C2H2) and Ca(OH)2. From the following enthalpy of reaction data and the standard enthalpy changes listed, calculate the AHOc for CaC2(s). (2 points) CaC2(s) +2H20(1) -> Ca(OH)2(s) C2H2(g) AH.2 kJ AH kJ/mol) H2O(g) -241.82 H20(1) -285.83 Ca(OH)2(s)--986.2 C2H2(g) +226.77
Consider the reaction CO(g) + 3H2(9)—CH (9) +H20(9) for which AH° = -206.1 kJ and A...
Consider the reaction CO(g) + 3H2(9)—CH (9) +H20(9) for which AH° = -206.1 kJ and A Sº = -214.7 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 1.982 moles of CO(g) react under standard conditions at 298.15 K. A Suniverse JK (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction...
Consider the reaction Fe(s) + 2HCl(aq)FeCl2(s) + H2(g) for which H° = -7.400 kJ and S°...
Consider the reaction Fe(s) + 2HCl(aq)FeCl2(s) + H2(g) for which H° = -7.400 kJ and S° = 107.9 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 1.552 moles of Fe(s) react under standard conditions at 298.15 K. Suniverse = J/K (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is...
b Consider the reaction: Ca(s) +2 H2001) + Ca(OH)2(aq) +2H2(g) -285.83 -1002.82 AH" (kJ/mol) S°(J/K) mol 41.59 69.95 -74.5 130.7 Is the reaction spontaneous at 298 K? AH° = -431.16 AS° = 5.41 AG° = -432.77 O Yes O No Submit Submit Answer Retry Entire Group 9 more group attempts remaining
This question has multiple parts. Work all the parts to get the most points. a Consider the reaction: Ca(s) +2 H20(1) - Ca(OH)2(aq) +2H2(g) AH:º(kJ/mol -285.83 -1002.82 S°(J/K) mol 41.59 69.95 -74.5 130.7 What are the values of AH°, ASand AG° AH° kJ/mol AS° = J/K.mol AG° = kJ/mol Submit Submit Answer Try Another Version 6 item attempts remaining
For the reaction Ca(OH)2(aq) + 2HCl(aq) +CaCl2(s) + 2H2O(1) AH° = -30.2 kJ and AS° = 205.9 J/K The maximum amount of work that could be done when 1.91 moles of Ca(OH)2(aq) react at 291 K, 1 atm is kJ. Assume that AH° and AS° are independent of temperature. Submit Answer Retry Entire Group 3 more group attempts remaining
Equations AS-re/T, AS system= ES® (products) - ES (reactants); AS univ=AS sys+AS sur; AGⓇ-AH- AGG products - Gractants; AGⓇ--RT In K TAS: Constants SJ/mol K): Na(s)=51.21, H20(1=69.95, NaOH(aq)-48.1, H2(g)=130.7 AHºr kJ/mol : Na(s)=0, H2O(I=-285.83, NaOH(aq)=-469.15, H2(g)=0 1) For the reaction: Na(s) + H2O(l) → NaOH(aq) + H2(g) at 298K a) Calculate AHºrn b) Calculate AS system c) Calculate AG® d) Explain why the reaction is favored by enthalpy, entropy favored, both or neither? e) Which direction does the equilibrium shift...
Calculate AG for the following reaction at 25°C. 2 Ca(s) + O2(g) → 2 Ca(s) (J/K mol) Substance AH (kJ/mol AG (kJ/mol) Ca(s) Ca2+(aq) CaO(s) Ca(OH)2(5) CaF2(5) CaCl(s) O(g) 028) O3(aq) Oz(8) -542.96 -635.6 -986.6 -1,214.6 -794.96 249.4 -553.0 -604.2 -896.8 -1,161.9 -750.19 230.1 41.6 -55.2 39.8 83.4 68.87 113.8 160.95 205.0 110.88 237.6 -12.09 142.2 16.3 163.4
help with this please
Ca(OH)2(aq) + 2 HCl(aq) +CaCl2(8) + 2 H2O(1) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K ANSWER: N2(g) + O2(g) +2NO(g) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K ANSWER: 2CO(g) + O2(g) +2002(9) - der e en manos de 20, ali ne more than one so mi dicogna undan Using standard thermodynamic data...
8. Calcium carbide (CaC2) reacts with water to form acetylene (C2H2) and Ca(OH)2. From the following enthalpy of reaction data and the standard enthalpy changes listed, calculate the AHOc for CaC2(s). (2 points) CaC2(s) +2H20(1) -> Ca(OH)2(s) C2H2(g) AH.2 kJ AH kJ/mol) H2O(g) -241.82 H20(1) -285.83 Ca(OH)2(s)--986.2 C2H2(g) +226.77
Consider the reaction CO(g) + 3H2(9)—CH (9) +H20(9) for which AH° = -206.1 kJ and A Sº = -214.7 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 1.982 moles of CO(g) react under standard conditions at 298.15 K. A Suniverse JK (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction...
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