Ans :-
Given equations are :
a). C (diamond) + O2 (g) --------------> CO2 (g) , ΔH1 = - 395.4 KJ
b). CO (g) + 1/2 O2 (g) ------------------> CO2 (g) , ΔH2 = - 283.0 KJ
c). C (graphite) + CO2 (g) --------------> 2 CO (g) , ΔH3 = + 172.5 KJ
The aim equation is : C (diamond) --------------> C (graphite) , ΔH = ?
Multiply the equation (b) by 2 and then add to equation (c) . Now, Subtract them in equation (a) to get the aim equation as :
Equation (a) - [ 2 x Equation (b) + Equation (c) ] , Because, ΔH is the additive property of the system therefore use the same conditions on ΔH to obtain the ΔH of aim equation as :
ΔH = ΔH1 - [ 2 x ΔH2 + ΔH3 ]
ΔH = - 395.4 KJ - [ 2 x (- 283.0 KJ) + 172.5 KJ ]
ΔH = - 395.4 KJ - [ - 566 KJ + 172.5 KJ ]
ΔH = - 395.4 KJ + 393.5 KJ
ΔH = - 1.9 KJ
Therefore, ΔH of the aim equation = -1.9 KJ |
carbon. Determine the AHrxn for C (diamond) → C (graphite), using the following thermochemical equations: a)...
Enter your answer in the provided box. Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Determine A Hrxn for C(diamond) — Сgraphite) with equations from the following list: (1) C(diamond) + O2(g) + CO2(g) (2) 2 CO2(g) → 2 CO(g) + O2(8) (3) C(graphite) + O2(g) → CO2(g) (4) 2 CO(g) → C(graphite) + CO2(g) AH=-395.4 kJ...
Diamon and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Determine delta H rxn for C(diamond) > C(graphite) with equations from the following list: Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Determine AHxn for C(diamond)...
19. Calculate AH° for the conversion of graphite into diamond from the following thermochemical equations. C(s, graphite) + O2(g) — C(s, diamond) + O2(g) CO2(g) AH° = -393.5 kJ + CO2(g) AH' = -395.9 kJ e uso -395.9 kJ +393.5 kJ -789.4 kJ +2.4 kJ -2.4 kJ
please help 4. You are given the following information. C (graphite) + O2 (g) - CO2 (g) CO(g) + 02 (9) - CO2 (g) Determine the standard enthalpy change for the reaction: C (graphite) + 02 (g) - CO(g) AH = - 393.5 kJ AH° = -283.0 kJ AHrxn = ?
1 out of 10 attemp Enter your ans wer in the provided box Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. DetermineA for rxn (diamond)- → C (graphite) C with equations from the following list: (1) Cdia (2) 2CO2(g)→2CO(g ) + O2(g) (3) C(graphite) +02(g)→CO2(g) (4) 2C0(g)→C(graphite) + CO2(g) AH AH-566.0 kJ AH--393.5 kJ AH--172.5kJ =-395.4 kJ...
4. You are given the following information. C (graphite) + O2(g) — CO2 (g) CO(g) + 02 (g) - CO2 (g) Determine the standard enthalpy change for the reaction: C (graphite) + / O2 (g) - CO (g) AH° = - 393.5 kJ AH° = - 283.0 kJ AHrxn = ?
5. Use the following data to determine the delta H for the conversion of diamond into graphite: C(diamind) (s) + O2(g) = CO2(g) delta H degrees = -395.4 kJ 2CO2(g) = 2 CO(g) + O2(g) delta H degrees = 566.0 kJ 2CO(g) = C(graphite) (s) + CO2 (g) delta H degrees = -172.5 kJ C(diamond) (s) = C(graphite) delta H degrees = ?
please help, i dont understand and need steps explainsd as well thank you Exercises: 3. Given the following two thermochemical equations, determine the AHºrxn,unknown. N2(g) +2 02(g) – 2 NO2(g) AH®rxn= 67 kJ NO(g) + 12 02(g) → NO2(g) AHºrxn=-56 kJ 4N2(g) + 402(g) → NO(g) AHºrxn,unknown= ? 4. Given the following two thermochemical equations, determine the AHrxn,unknown. Fe2O3(s) + 3 CO(g) – 2 Fe(s) + 3 CO2(g) AH°rxn=-26.7 kJ CO(g) + 42 02(g) → CO2(9) AH°rxn=-283.0 kJ 2 Fe(s)...
Determine the enthalpy change for C(graphite) + O2(g) → CO2(g); AH= ? using the following three thermochemical equations, which will be referred to as reactions (A), (B), and (C). (A) Sro(s) + CO2(g) → SCO3(s);AH = -234 kJ (B) 2Sro(s) → 25r(s) + O2(g); AH= 1184 kJ (C) 2SrCO3(s) — 25r(s) + 2C(graphite) + 302(g); AH= 2440 kJ The value for AH = List what action you performed on each equation to achieve your goal. Equation (A) was Equation (B)...
Based on the following equations: 2 CO2(g) + O2(g) + 2 CO (g) AH- +566.0kJ 2(graphite) + O2(g) + 2 CO (5) AH = -221.0 kJ Determine the enthalpy change (AH) for the following reaction: C(graphite) + O2 (8) CO2(g)