Homework Answers
Let the speed be v,
By energy conservation,
kQ1Q2/r1 - kQ1Q2/x2 = 0.5mv^2
2*9e9*1.2e-6*3.75e-6/[sqrt(0.03^2 + 0.03^2] - 2*9e9*1.2e-6*3.75e-6/[sqrt(0.03^2 + 0.07^2]
=0.5*10e-6*v^2
v = 411 m/s answer
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