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Imagine an alternate universe where the value of the Planck constant is 6.62607 x 10 J.s. | In that universe, which of the fo

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Answer #1

\lambda = h/p

\lambda(car) = 6.62607×10-38/(2000×140×1000/3600)

= 8.52×10-43 m ( the wavelength is negligible compared to dimensions of car . Hence the object can be adequately described by classical mechanics ) Answer: classical

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\lambda(virus) = 6.62607×10-38/(4.6×10-17×10-3 × 0.70×10-6) = 2.06×10-12 m = 0.0021nm ( wavelength is very small compared to dimension to virus ) . Hence classical mechanics can explain it's behavior . Answer: classical

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\lambda(atom) = 6.62607×10-38/(1.0×10-26×236) = 2.81×10-14 m = 2.81 pm ( wavelength is not negligible compared to size of atom, quantum mechanics is required .) Answer: quantum

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\lambda(mosquito) = 6.62607×10-38/(2.5×10-6×3.2) = 8.28×10-33 m

Wavelength is neglible compared to its size . Hence classical mechanics can explain it's behavior .

Answer: classical

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