Hi
We should remember that the wavelength is given by h/p
It we see the wavelength in all cases
Case 1
Wavelength =(6.6*10^-6 )/(1*10^-26*1.75 )= 3.77*10 ^18 m
Case 2
Case 2
Wavelength(6.6*10^-6 )/(3*10^8*(560÷3600))
=1.41 *10^-13 m
Case 3
Wavelength(6.6*10^-6 )/((5.8/1000)*3.3)
=3.44 *10^-4
Case 4
Wavelength(6.6*10^-6 )/(23*10^-6*8.5)
=0.03 m
We can see that in the case 2 we have the wavelength that is quite
small to be notice so we can't apply the quantum theory and thus we
need to use the classical theory.
In all other case we can use the quantum theory.
Hope this helps
Feel free to comment in the case of any doubt.
Thank you
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