Consider the following hypothesis test:
H 0: 20
H a: < 20
A sample of 60 provided a sample mean of 19.5. The population standard deviation is 2.
a. Compute the value of the test statistic (to
2 decimals). If your answer is negative, use minus "-"
sign.
b. What is the p-value (to 3
decimals)?
c. Using = .05, can it be concluded that the population mean is less than 20? SelectYesNoItem 3
d. Using = .05, what is the critical
value for the test statistic (to 3 decimals)? If your answer is
negative, use minus "-" sign.
What is the rejection rule using the critical value?
Reject H 0 if z Select≤≥=Item 5
e. What is your conclusion?
Reject H 0 if z is Selectgreater than
or equal togreater thanless than or equal toless thanequal tonot
equal toItem 7 the critical value.
Below are the null and alternative Hypothesis,
Null Hypothesis: μ = 20
Alternative Hypothesis: μ < 20
a)
Test statistic,
z = (xbar - mu)/(sigma/sqrt(n))
z = (19.5 - 20)/(2/sqrt(60))
z = -1.94
b)
P-value Approach
P-value = 0.0262
c)
As P-value < 0.05, reject the null hypothesis.
Yes, can be concluded
d)
Rejection Region
This is left tailed test, for α = 0.05
Critical value of z is -1.645.
e)
Hence reject H0 if z < -1.645
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