Part a)
Test Statistic :-
Z = ( X̅ - µ ) / ( σ / √(n))
Z = ( 14.15 - 15 ) / ( 4 / √( 50 ))
Z = -1.50
Part b)
P value = 2 * P ( Z > 1.50 ) = 2 * 1 - P ( Z < 1.50 ) = 0.1329
Looking for the value Z = 1.50 in standard normal table to find the P value
Part c)
Decision based on P value
Reject null hypothesis if P value < α = 0.05 level of
significance
Since 0.1329 > 0.05, hence we fail to reject
null hypothesis
Result :- We fail to reject null hypothesis
Part d)
Critical value Z(α/2) = Z( 0.05 /2 ) = ± 1.96
Test Criteria :-
Reject null hypothesis if | Z | > Z( α/2 ) i.e Z <
-1.96 OR Z > 1.96
| Z | > Z( α/2 ) = 1.50 < 1.96
Result :- Fail to reject null hypothesis
Reject null hypothesis if Z < -1.96 OR Z > 1.96
Consider the following hypothesis test: Ho: u = 15 Hai ji #15 A sample of 50...
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