subtracting equation 1 from 2 the equation obtained is
thus change in enthalpy for the reaction is
ΔH total = ΔH2 - ΔH1 = -271.67 - (-65.19) = -206.48 KJ
1. Determine: Ca(OH)2 (s) + H2SO4 (1) → CaSO4 (8) + 2 H20 (1) Given: CaO...
2. (10 pts) Given the following data Ca(s)2C(graphite)CaC2(s) -62.8 kJ OH635.5 Ca(s)1/202(g) CaO(s) kJ CaO(s)H20()- Ca(OH)2(aq) OH 653.1 kJ 2CO2(g)H2O(l OH1300 C2H2(g)5/202(g) kJ C(graphite) O2(g)CO2(g) H= -393.5 kJ calculateH for the reaction (show your work for full credit) CaC2(s)+ 2H20()- Ca(OH)2(aq) CH2(g)
Consider the following chemical equation: Ca(OH)2 (aq) + H2SO4 (aq) + CaSO4 (s) + H20 (1) Identify the type(s) of chemical reaction that this is classified as. precipitation + acid-base precipitation + oxidation-reduction (redox) precipitation acid-base oxidation-reduction (redox)
81. Given the following data Ca(s) + 2C(graphite) → CaC2(s) AH-62.8 kJ Ca(s) + cao(s) + H2O(l)-→ Ca(OH)2(aq) C2H2(g) +022CO2(8)+ H200) 2(g)-→ CaO(s) ΔH =-635.5 kJ ΔH =-653.1 kJ C(graphite) + 02(g)-→ CO2(g) ΔH =-393.5 kJ calculate ΔH for the reaction CaC2(s) + 2H20() → Ca(OH)2(aq) + C2H2(g)
RULES 1. If reverse equation, change sign of AH value. 2. If double equation, double AH value. 3. If halve equation, halve AH value. 4. NOTE that as states (solid, liquid, or gas) change, energy is absorbed or released so AH values likewise change. 5. AH' - O for all elements in their most stable form at 1 atm. pressure and 25°C. 6. AH is calculated as ZAHproducts. ZAHreactants. Rearrange the thermochemical equations given to determine the AH value for...
8. Calcium carbide (CaC2) reacts with water to form acetylene (C2H2) and Ca(OH)2. From the following enthalpy of reaction data and the standard enthalpy changes listed, calculate the AHOc for CaC2(s). (2 points) CaC2(s) +2H20(1) -> Ca(OH)2(s) C2H2(g) AH.2 kJ AH kJ/mol) H2O(g) -241.82 H20(1) -285.83 Ca(OH)2(s)--986.2 C2H2(g) +226.77
c is the reaction: Ca(s) + 2 H20(1) Ca(OH)2(aq) + 2H2(8) -285.83 -1002.82 AH °(kJ/mol) S°(J/K) mol 41.59 69.95 -74.5 130.7 AH° = -431.16 AS° = 5.41 AG° = -432.77 enthalpy favored Oneither enthalpy and entropy favored O entropy favored O both enthalpy and entropy favored Submit
Using the equations Ca (s)2 O (g) Сао (s) 2 H2 (g) Determine the enthalpy for the reaction Са (s) + 2 H0 () — Са(ОН)2 (s) + H2 (9). CaO (s) AH° = -635 kJ/mol -64 kJ/mol H2O ()Ca(OH)2 (s) AH O2 (g)2 H2O (I) AH° = -572 kJ/mol kJ/mol 1 2 3 4 6 C 5 7 8 9 +/- 0 x 100 LO 11.01 g of MgSO4 is placed into 100.0 mL of water. The water's temperature...
Calcium oxide and water react in an exothermic reaction: CaO(s) + H2O(l) >>>>>>>> Ca(OH)2(s) Heat of reaction (Rxn) = -64.8 kJ/mol How much heat would be liberated when 7.15 g CaO(s) is dropped into a beaker containing 152 g H2O. A. 1.97 x 10 to the third kJ B. 508 kJ C. 8.26 KJ D. 547 KJ E. 555 kJ
How much heat is released if 7.15 g Cao(s) is added to 152 g of H2O(l)?! Cao(s) + H2O) - Ca(OH)2(s) AHxn = -64.8 kJ/mol Select one: a. 7.68 kJ O b.8.26 kJ O c. 508 kJ d. 547 kJ O e. 555 kJ
How much heat is released if 7.15 g Cao is added to excess H2O? CaO + H2O + Ca(OH)2 AH = – 64 .8 kJ/mol