Question

Part A Calculate the number of moles of Ag+ in 5.00 mL of 2.00x10-3M AgNO3 and the number of moles of Crok in 5.00 mL of 3.50x10-3 M K Cr04. Input your answers separated by a comma. IPO AQ R o 2 ? mol Submit Request Answer

Answer 1

1)

Mol of AgNO3 = M(AgNO3)*V(AgNO3) in L

= 2.00*10^-3 M * 5.00*10^-3 L

= 1.00*10^-5 mol

1 mol of AgNO3 has 1 mol of Ag+

So,

Mol of Ag+ = 1.00*10^-5 mol

2)

1)

Mol of K2CrO4 = M(K2CrO4)*V(K2CrO4) in L

= 3.50*10^-3 M * 5.00*10^-3 L

= 1.75*10^-5 mol

1 mol of K2CrO4 has 1 mol of CrO42-

So,

Mol of CrO42- = 1.75*10^-5 mol

Answer: 1.00*10^-5, 1.75*10^-5