Question

Ablock of mass m,-1.9 kg is held againsta spring ofspring constantk=410 N/m and compressedx frictionless surface towards mass m2 4.3 kg. The two masses collide and mass mi rebounds back towards the spring at a speed of 2.1 m/s, while mass m2 slides up the frictionless hill. 3/ 0.75 m. When released, it is pushed along the a. What is the speed of mass mi right before the collision? b. What is the speed of mass m2 after the collision? c. How high up the hill does mass m2 go before stopping? d. Mass m2 slides back down the hill and collides and sticks with mass mi, e. f. g. now sitting at rest at the equilibrium position of the spring. How far do they compress the spring? Calculate the change in kinetic energy in the first collision. What type of collision is the first collision? Explain. What type of collision is the second collision? Explain.

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Answer #1

This problem is an application of linear momentum conservation and energy conservation.

Q 3 上っ before cellision Tan+→ (b) ing Limar Momutun Conservation (19 (11-0)(12) +(4.)V Se ayer cellision Pant., (e) Using, enegy conservation- 2. | 1.-7/4 mje_ Height attained 2 Part-td) ing linear momustum csndeah on mV.43x5 797-4.0205 m/s ,m439 つv,2. 0.4944 m

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