An iron bar of mass, 0.57 kg, slides down a frictionless incline 0.66 m high. At the bottom of the incline it collides and sticks to a magnet of mass, 1.28 kg. What is the speed of the combined masses after collision.
here ,
h = 0.66 m
let the speed of iron bar at the bottom is u m/s
Now , Using conservation of energy
0.5 * m*u^2 = m*g*h
u = sqrt(2*0.66*9.8)
u = 3.6 m/s
Now , let speed of combined masses is v m/s
Using conservation of momentum
3.6 * 0.57 = (0.57 + 1.28)* v
v = 1.11 m/s
the speed of combined masses is 1.11 m/s
As the bar moves 0.66 meter down, its kinetic energy increases
as its potential energy decreases.
KE =
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