Homework Answers
mass of HBr = volume * density
= 4.6*1.49
= 6.854g
no of moles of HBr = W/G.M.Wt
= 6.854/80.908 = 0.0847moles
mass of 1-butanol = volume * density
= 3*0.81 = 2.43g
no of moles = W/G.M.Wt
= 2.43/74.12 = 0.03278 moles
C4H9OH + HBr -------------. C4H9Br + H2O
1 mole of HBr react with 1 mole of 1- butanol
0.0847 moles of HBr react with 0.0847 moles of 1-butanol is required
1-butanol is limiting reagent
1 mole of 1-butanol react with excess of HBr to gives 1mole of 1-bromobutane
0.03278 moles of 1-butanol react with excess of HBr to gives 0.03278 moles of 1-bromobutane
mass of 1-bromobutane =no of moles * gram molar mass
= 0.03278*137 = 4.49g of 1-bromobutane
Theoretical yield of 1-bromobutane = 4.49g
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Part 1 of 4 - Question 1 of 4 0.5 Points Using 48% HBr (80.908 g/mol,...
SIITTIUSSUTI-BUTIL BRUMIDE CH3CH2CH2CH2OH + HBr CH3CH2CH2CH2Br+H2O H2SO4 1-Butanol Hydrobromic Acid 1-Bromobutane Bp 118°C Den 1.49 Bp...
SIITTIUSSUTI-BUTIL BRUMIDE CH3CH2CH2CH2OH + HBr CH3CH2CH2CH2Br+H2O H2SO4 1-Butanol Hydrobromic Acid 1-Bromobutane Bp 118°C Den 1.49 Bp 101.6°C Den 0.810 MW 80.9 Den 1.275 (a)which is the limiting reagent, (b) Calculate the theoretical yield, and (c) percent yield of the above reaction if you were to react 48 mmol of 1-Butanol with 66 mmol of aqueous hydrobromic acid and you obtained 3.7g of 1-Bromobutane? SHOW ALL CALCULATIONS (a) Theoretical Yield: (b) Limiting Reagent: (c) Percent Yield:
CH,CH:CH.CН,ОН + НBr CH&CH2CH2CH2Br + H2O H2SO4 1-Butanol Hydrobromic Acid 1-Bromobutane Вр 118° C Den 1.49...
CH,CH:CH.CН,ОН + НBr CH&CH2CH2CH2Br + H2O H2SO4 1-Butanol Hydrobromic Acid 1-Bromobutane Вр 118° C Den 1.49 Вр 101.6° С Den 0.810 MW 80.9 Den 1275 (a)which is the limiting reagent, (b) Calculate the theoretical yield, and (e) percent yield of the above reaction if you were to react 48 mmol of 1-Butanol with 66 mmol of aqueous hydrobromic acid and you obtained 3.7g of 1-Bromobutane? SHOW ALL CALCULATIONS (a) Theoretical Yield: (b) Limiting Rcagent: (c) Percent Yield:
CHEM2123 / Pre-Lab Study Questions / Exp. #7 SYNTHESIS OF N-BUTYL BROMIDE CH3CH2CH2CH2OH + HB CH3CH2CH2CH2Br+H20 H2...
CHEM2123 / Pre-Lab Study Questions / Exp. #7 SYNTHESIS OF N-BUTYL BROMIDE CH3CH2CH2CH2OH + HB CH3CH2CH2CH2Br+H20 H2SO4 1-Butanol Hydrobromic Acid 1-Bromobutane Bp 118°C Den 1.49 Bp 101.6°C Den 0.810 MW 80.9 Den 1.275 (a)which is the limiting reagent, (b) Calculate the theoretical yield, and (c) percent yield of the above reaction if you were to react 48 mmol of 1-Butanol with 66 mmol of aqueous hydrobromic acid and you obtained 3.7g of 1-Bromobutane? SHOW ALL CALCULATIONS (a) Theoretical Yield: (b)...
please clearly explain how to do this using the below information with thr correct sig figs...
please clearly explain how to do this using the below
information with thr correct sig figs
Ba Convert 0.1290 mol of sodium bromide to mmol of sodium bromide b. Convert 0.1290 mol of sodium bromide to grams. nwart 225.0 mmol of sulfuric acid to ml of sulfuric acid. (hint-you will use the formula mass AND density in the conversion.) 5. a. Determine the theoretical yield (IN GRAMS) for 1-bromobutane if you start with 109 mmol of butanol and excess acid...
6. (25 pts) (a) Calculate the theoretical yield, (b) limiting reagent, and (c) percent yield of the above reaction i...
6. (25 pts) (a) Calculate the theoretical yield, (b) limiting reagent, and (c) percent yield of the above reaction if you were to react 48 mmol of 1-Butanol with 60 mmol of aqueous hydrobromic acid and you obtained 4.1g of 1-Bromobutane? SHOW ALL CALCULATIONS (a) Theoretical Yield: (b) Limiting Reagent: (c) Percent Yield:
Carbon-hydrogen bonds exhibit a range of different chemical reactivity that depends on molecular structure. Classify the...
Carbon-hydrogen bonds exhibit a range of different chemical reactivity that depends on molecular structure. Classify the C-H bonds at the carbons labeled a-c in the structure below. Possible classifications are: primary, secondary, & tertiary or none if there are no hydrogens at the labeled carbon. C-H bond(s) at a C-H bond(s) at b or C-H bond(s) at v primary secondary tertiary 2 item attempts Submit Answer Try Another Version none 1-Bromopropane was prepared by heating 11.1 g of sodium bromide...
3 part question Determine the theoretical yield (IN GRAMS) for 1-bromobutane if you start with 109...
3 part question
Determine the theoretical yield (IN GRAMS) for 1-bromobutane if you start with 109 mmol of butanol nd excess acid and sodium bromide. (Note: the stoichiometric relationship between butanol and romobutane is 1:1) Convert the theoretical yield of 1-bromobutane to moles. Convert the moles to mmol. please clearly explain how to do this using the below information with thr correct sig figs Structure for 1-butanol Molecular weight for 1-butanol density for 1-butanol Bonpoint butanol 117.7°C 74.12 gimol 81...
Compound molar mass density volume mmol equ 21% sodium ethoxide in ethanol 68.05 g/mol 0.868 g/mL...
Compound molar mass density volume mmol equ 21% sodium ethoxide in ethanol 68.05 g/mol 0.868 g/mL 20 mL ~1.3 *1-bromobutane 137.02 g/mol 1.276 g/mL 4.5 mL ~1.0 *Limiting Reagent: 1-bromobutane I need help finding the mmol of sodium ethoxide in ethanol and 1-bromobutane. Also how to find the theoretical yield of this reaction from this graph?
0.339 is correct answer? Question 5 of 5 0.5 Points 0.26 gram of salicylic acid, and...
0.339 is correct answer?
Question 5 of 5 0.5 Points 0.26 gram of salicylic acid, and 0.668 mL of acetic anhydride (d = 1.082g/mL) react in the presence of an acid catalyst to produce acetylsalicylic acid. Determine the limiting reagent and then calculate the theoretical yield of the product in grams. Report the theoretical yield to three decimal places.
The Hbr solution utilzed is 48% HBr by weight. The density is 1.49 g/mol. The volume...
The Hbr solution utilzed is 48% HBr by weight. The density is 1.49 g/mol. The volume used is 2.1 ml. Determine the moles of HBr used
SIITTIUSSUTI-BUTIL BRUMIDE CH3CH2CH2CH2OH + HBr CH3CH2CH2CH2Br+H2O H2SO4 1-Butanol Hydrobromic Acid 1-Bromobutane Bp 118°C Den 1.49 Bp 101.6°C Den 0.810 MW 80.9 Den 1.275 (a)which is the limiting reagent, (b) Calculate the theoretical yield, and (c) percent yield of the above reaction if you were to react 48 mmol of 1-Butanol with 66 mmol of aqueous hydrobromic acid and you obtained 3.7g of 1-Bromobutane? SHOW ALL CALCULATIONS (a) Theoretical Yield: (b) Limiting Reagent: (c) Percent Yield:
CH,CH:CH.CН,ОН + НBr CH&CH2CH2CH2Br + H2O H2SO4 1-Butanol Hydrobromic Acid 1-Bromobutane Вр 118° C Den 1.49 Вр 101.6° С Den 0.810 MW 80.9 Den 1275 (a)which is the limiting reagent, (b) Calculate the theoretical yield, and (e) percent yield of the above reaction if you were to react 48 mmol of 1-Butanol with 66 mmol of aqueous hydrobromic acid and you obtained 3.7g of 1-Bromobutane? SHOW ALL CALCULATIONS (a) Theoretical Yield: (b) Limiting Rcagent: (c) Percent Yield:
CHEM2123 / Pre-Lab Study Questions / Exp. #7 SYNTHESIS OF N-BUTYL BROMIDE CH3CH2CH2CH2OH + HB CH3CH2CH2CH2Br+H20 H2SO4 1-Butanol Hydrobromic Acid 1-Bromobutane Bp 118°C Den 1.49 Bp 101.6°C Den 0.810 MW 80.9 Den 1.275 (a)which is the limiting reagent, (b) Calculate the theoretical yield, and (c) percent yield of the above reaction if you were to react 48 mmol of 1-Butanol with 66 mmol of aqueous hydrobromic acid and you obtained 3.7g of 1-Bromobutane? SHOW ALL CALCULATIONS (a) Theoretical Yield: (b)...
please clearly explain how to do this using the below
information with thr correct sig figs
Ba Convert 0.1290 mol of sodium bromide to mmol of sodium bromide b. Convert 0.1290 mol of sodium bromide to grams. nwart 225.0 mmol of sulfuric acid to ml of sulfuric acid. (hint-you will use the formula mass AND density in the conversion.) 5. a. Determine the theoretical yield (IN GRAMS) for 1-bromobutane if you start with 109 mmol of butanol and excess acid...
6. (25 pts) (a) Calculate the theoretical yield, (b) limiting reagent, and (c) percent yield of the above reaction if you were to react 48 mmol of 1-Butanol with 60 mmol of aqueous hydrobromic acid and you obtained 4.1g of 1-Bromobutane? SHOW ALL CALCULATIONS (a) Theoretical Yield: (b) Limiting Reagent: (c) Percent Yield:
Carbon-hydrogen bonds exhibit a range of different chemical reactivity that depends on molecular structure. Classify the C-H bonds at the carbons labeled a-c in the structure below. Possible classifications are: primary, secondary, & tertiary or none if there are no hydrogens at the labeled carbon. C-H bond(s) at a C-H bond(s) at b or C-H bond(s) at v primary secondary tertiary 2 item attempts Submit Answer Try Another Version none 1-Bromopropane was prepared by heating 11.1 g of sodium bromide...
3 part question
Determine the theoretical yield (IN GRAMS) for 1-bromobutane if you start with 109 mmol of butanol nd excess acid and sodium bromide. (Note: the stoichiometric relationship between butanol and romobutane is 1:1) Convert the theoretical yield of 1-bromobutane to moles. Convert the moles to mmol. please clearly explain how to do this using the below information with thr correct sig figs Structure for 1-butanol Molecular weight for 1-butanol density for 1-butanol Bonpoint butanol 117.7°C 74.12 gimol 81...
0.339 is correct answer?
Question 5 of 5 0.5 Points 0.26 gram of salicylic acid, and 0.668 mL of acetic anhydride (d = 1.082g/mL) react in the presence of an acid catalyst to produce acetylsalicylic acid. Determine the limiting reagent and then calculate the theoretical yield of the product in grams. Report the theoretical yield to three decimal places.
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