Question

CHEM2123 / Pre-Lab Study Questions / Exp. #7 SYNTHESIS OF N-BUTYL BROMIDE CH3CH2CH2CH2OH + HB CH3CH2CH2CH2Br+H20 H2SO4 1-Butanol Hydrobromic Acid 1-Bromobutane Bp 118°C Den 1.49 Bp 101.6°C Den 0.810 MW 80.9 Den 1.275 (a)which is the limiting reagent, (b) Calculate the theoretical yield, and (c) percent yield of the above reaction if you were to react 48 mmol of 1-Butanol with 66 mmol of aqueous hydrobromic acid and you obtained 3.7g of 1-Bromobutane? SHOW ALL CALCULATIONS (a) Theoretical Yield: (b) Limiting Reagent: (c) Percent Yield:

Answer 1

chCh, Cn Cn,B +H20 СИз Ст, Ст, си,ои +ИЗ8 12soy ste irnd limiting Reagat. a malu her oficient of CnC, C,, o males Cafficient b)males heu lafficent of HBr 66m 4 mol 48 1 66 48 466 1- Butanal acti ca limiting veagat S0 Steh Hind theorctical yeild. afplied POAC Rule on abave Ron. mole of -Butanal cabBicdent masof -Bromobatans males of 1-Bromobutare Cofficient 48 X1o-3 malar mals Y 137-9/mal molar madsof1-Boomabustane masu of 1-Bromobatane 48Xlo137 6.576 9 oI-Bromabutue mads

bo Theoretical yeild = 6.5769 Stop ird idd y. %yield- actual field XloO Theoretiel yield 3.7 X/O0 6.546 56.27 % 1 % yeild of this Reaction s 56.27 Thank you Hay this tul yau