A positive charge of 4.80 μC is fixed in place. From a distance of 3.40 cm a particle of mass 5.20 g and charge +3.70 μC is fired with an initial speed of 66.0 m/s directly toward the fixed charge. How close to the fixed charge does the particle get before it comes to rest and starts traveling away?
Solution :-
Given data:-
first charge = 4.8 uC
second charge = 3.7 uC
distance = 4.4 cm
mass = 5.2 gm
velocity = 66 m/s
initial energy = kinetic energy + electric potential energy
initial energy = 0.5 * 5.2 * 10^-3 * 66^2 + 9 * 10^9 * 4.8* 10^-6 * 3.7 * 10^-6 / 0.034
initial energy = 16.026 J
final energy = electric potential energy
final energy = 9 * 10^9 * 4.8* 10^-6 * 3.7 * 10^-6 / x
by conservation of energy
final energy = initial energy
9 * 10^9 * 4.8 * 10^-6 * 3.7 * 10^-6 / x = 16.026
x = 0.00997m
particle will come 0.997 cm close to fixed
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