Use bond energies from this table to estimate the heat of
reaction for the following process:
Homework Answers
On reactant side we have:
4 C-H bond
1 C=C bond
1 Cl-Cl bond
On product side we have:
4 C-H bond
1 C-C bond
2 C-Cl bond
Use:
Delta H = BE(reactant) - BE(product)
= 4*BE(C-H) + 1*BE(C=C) + 1*BE(Cl-Cl) - 4*BE(C-H) - 2*BE(C-Cl) - 1*BE(C-C)
= 1*BE(C=C) + 1*BE(Cl-Cl)- 2*BE(C-Cl) - 1*BE(C-C)
= 1*615 + 1*240 - 2*330 - 1*345
= -150 KJ/mol
Answer: -150 KJ/mol
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