Question

A hand pushes a 4 kg block along a table from point A to point C as shown in the figure below. The table has been prepared so that the left half of the table (from A to B) is frictionless. The right half (from B to C) has a non-zero coefficient of friction equal to u. The hand pushes the block the full distance from A to C using a constant force of 7 N. The block starts off at rest at point A and comes to a stop when it reaches point C. The distance from A to B is 0.5 m and the distance from B to C is also 0.5 m. We will consider the block by itself as our system so all forces on the block are external. Initial position of block final position of block M no friction s friction V B -12 m -142 m

Answer 1

since the number of parts to be answered is not specified hence answering the first 4 questions

. 1 F = 7 V img Since there is no friction in the block will acceleration AB hence in AB. HB = B C = 0.5m. work done in pushing = fod = 7x0.5= 3.5J | Change in kinetic energy = work done on block = 3. 5J :: Final KE - Initial Ke = 3.5 Since Initicel KE = 0 and at B velocity = re Į mv²= 3.5 m= 4 kg v = 1.32 m/s. Since pushing hence work force remains same = 70 done while BC due to pushing 7X0.5=3.5 J =