Question

A block with mass of 10 kg is on a frictionless surface. One hand on the left side of the block is pushing it to the right. A second hand on the right side of the block is pushing it to the left.

The block starts from rest. Then Hand 1 pushes with a force of 8 N and the block moves to the right a distance of 4 m, where it has a final velocity of 2 m/s. Between its initial and final positions, how much work did Hand 2 do?

A block with mass of 10 kg is on a frictionless surface. One hand on the left side of the block is pushing it to the right. A

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Answer #1

i dium 4m - Wf, tWf2 = AKE. fid+Wf2 = //mv2o 8x4 t W of 2 = 1x10x22 Wife = 20-32=-125 Wp =125 Wf, = fid = work done by Hand 1

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