12. A reaction has Ea = 50.0 kJ mol G1. If the
specific rate constant (k)
for this reaction is 0.00365 s G1 at 25 o C, what will the value of
the
specific rate constant be at 100EC ?
Given:
T1 = 25 oC
=(25+273)K
= 298 K
T2 = 100 oC
=(100+273)K
= 373 K
K1 = 3.65*10^-3 s-1
Ea = 50 KJ/mol
= 50000 J/mol
use:
ln(K2/K1) = (Ea/R)*(1/T1 - 1/T2)
ln(K2/3.65*10^-3) = (50000.0/8.314)*(1/298 - 1/373.0)
ln(K2/3.65*10^-3) = 6014*(6.747*10^-4)
ln(K2/3.65*10^-3) = 4.058
(K2/3.65*10^-3) = e^(4.058)
(K2/3.65*10^-3) = 57.85
K2 = 0.2112 s-1
Answer: 0.211 s-1
12. A reaction has Ea = 50.0 kJ mol G1. If the specific rate constant (k)...
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