Question

11. The magnitude of the force of a 400 N/C electric field on a 002 oint ctharge is A) 8 N B) 5 x 10 N C) 8x 10*N D) 008 N

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Answer #1

Solution:

=> using the formula = F = E *Q

=> F = 400*0.02

=> F = 8 N

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