3. Calculate AH for the reaction Ato AL120103 N2O(g) + NO2(g) → 3 NO(g) from the...
Given the following equation, N2O(g) + NO2(g) → 3 NO(g) AG°/x = -23.0 kJ Calculate AGºrxn for the following reaction. CHO COURO 3 NO(g) + N2O(g) + NO2(g) 153 ou te ato O bbou n esto bancabies A) -23.0 kJSOU nude au CODE B) 69.0 kJ e je bom su se 159 Hou e ab C) -69.0 kJ D) -7.67 kJ ost adapun E) 23.0 kj
Calculate AH for the reaction N2H4(0) + O2(g) → N2(g) + 2 H2O(1) given the following data: Equation AH (kJ) 2 NH3(g) + 3 N2O(g) → 4 N2(g) + 3 H2O(l) -1010 N2O(g) + 3 H2(g) → N2H4(1) +H2O(1) -317 2 NH3(g) + 1202(g) → N2H4(1) + H20(1) -143 H2(g) + 1202(g) → H2O(H -286 AH=
18. Consider the following data.
2 NO(g) N2(g) + O2(g)
H = -180.7 kJ
2 NO(g) + O2(g)
2 NO2(g)
H = -113.1 kJ
2 N2(g) +
O2(g) 2 N2O(g)
H = +163.2 kJ
Use Hess's law to calculate H for the reaction below.
3 NO(g) N2O(g) + NO2(g)
H = ______________ kJ
Given the following equation, N2O(g) + NO2(g) → 3 NO(g) ΔG°rxn = -23.0 kJ Calculate ΔG°rxn for the following reaction. 18 NO(g) → 6 N2O(g) + 6 NO2(g) -3.83 kJ -23.0 kJ 138 kJ -138 kJ 23.0 kJ
Given the following equation, N2O(g) + NO2(g) → 3 NO(g) ΔG°rxn = -23.0 kJ Calculate ΔG°rxn for the following reaction. 18 NO(g) → 6 N2O(g) + 6 NO2(g) -3.83 kJ -138 kJ 23.0 kJ -23.0 kJ 138 kJ
Question 62 Calculate the enthalpy change for the following reaction: NO(g) + O(g) - NO2(g) from the following data: NO(g) + O3(g) – NO2(g) + O2(g) O3(g) – 1.502(g) O2(g) - 20(g) AH = -198.9 kJ AH = -142.3 kJ AH = 495.0 kJ 0-304.1kJ 438.4 kJ 190.9 kJ 153.8 kJ O -551.6 kJ
(ii) Calculate AH° for the reaction N2H4(1) + O2(g) → N2(g) + 2H2O(1) using the data given below: 2NH3(g) + 3N2O(g) → 4N2(g) + 3H2O(1) N2O(g) + 3H2(g) → N2H4(l) + H2O(1) 2NH3(g) + O2(g) → N2H4(1) + H2O(1) H2(g) + 1/2O2(g) → H2O(1) AH° = -1010. kJ AH° = -317 kJ AH° = -143 kJ AH° = -286 kJ
uations, calculate AH°rxn for the reaction: (3 marks) LFrom the following thermochemical eq So2(g)+NO2(8) SO3(8)+NO(g) 2 SO28)+02(8)-2SO3(8) 2N0(g) + O2(g. 2 NO2(g) A rxn--197.8 kJ Δ//orxn®-114, 14 kJ -SMB, eus e ,
1. Calculate AH for the reaction C2H4 (8) + H2() → C2H6), from the following data. C2H4 (g) + 3 02 (®) → 2 CO2 (s) + 2 H20 (1) C2H6 (g) + 7/2 02(g) → 2 CO2(g) + 3 H20 (1) H2 + 1/2O2() → H20 (1) AH = -1411. kJ/mole AH = -1560. kJ/mole AH = -285.8 kJ/mole 2. Calculate AH for the reaction 4 NH3(g) +502 (g) → 4 NO(g) + 6 H20 (g), from the following...
From the following equations, calculate AH for the reaction 2N2(g) + + 5O2(g) → 2N2O5(g) AH = ? H2(g) + O2(9) H206) AH = -285.8 kJ N2O5(g) + H200 2HNO30 AH = -76.6 kJ N2(g) + 302(g) + H219) - 2HNO30) AH = -348.2 kJ