Question

EXPERIMENT 9: SYNTHESIS OF DIPHENYLACETYLENE Objective: Complete the two-step halogenation/elimination reaction sequence that converts an alkene (trans- stilbene) to an alkyne (diphenylacetylene)
numbers 3-5 please

Those are the three equations given to us and that is the reaction mechanism as well as the procedure. there is nothing else i can give you

Answer 1

solution: The given reaction is Br ③ This reaction is performed in the presence of strong base Mechanism: step-1 - Br KOH (2) tmajor) (minor) (E) (major) goes In basic condition it under elimination reaction to two isomer E and z . E isomer is major and a as compared to z isomer because of steric hindrance give is major and more stable step. 2 Br Kot attached to sp² carbon is not that much acidic The hydrogen atom the reaction in to abstract by weak buse. By use of strong base heating the reaction forwad to product elkyene alkyne. to 6 khen 20 mL deionised water to add above reaction form pricipitute because the product of elimination reaction is alkyne it is unsaturated hydrocarbon do not contain any polar functional That is group. it is Is non-polar and only soluble in organic the deionise water solvent. When add the koh will soluble in water and organic dissolve in like. . and form pricipitate. Principle like part will come out from water and form pricipitate.