Answer:
Given,
S.No | X | (xi-xbar)^2 |
1 | 56 | 142.0864 |
2 | 62 | 35.0464 |
3 | 87 | 364.0464 |
4 | 74 | 36.9664 |
5 | 71 | 9.4864 |
6 | 74 | 36.9664 |
7 | 19 | 2393.1664 |
8 | 56 | 142.0864 |
9 | 79 | 122.7664 |
10 | 79 | 122.7664 |
11 | 83 | 227.4064 |
12 | 75 | 50.1264 |
a)
Mean = x / n
= (56+62+87+74+71+74+19+56+79+79+83+75)/12
= 815/12
Mean = Xbar = 67.92
b)
Standard deviation = sqrt((xi-xbar)^2 / (n-1))
substitute values
= sqrt((142.0864+35.0464+364.0464+36.9664+9.4864+36.9664+2393.1664+142.0864+122.7664+122.7664+227.4064+50.1264) / (12 - 1))
= 18.2978
Standard deviation = 18.2978
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