Question

Please include a screenshot of the Excel sheet and the equations used to complete the table. Thank you so much!

(14 points) The conductivity data, below, was obtained for the dissociation of (CH3).SnCl in ethyl alcohol solution at 25.0°C. a. Complete the table, using Excel. 1 cm = 1 mL. b. Construct the appropriate plot and linear regression (include the equation and R?). c. Determine the limiting molar conductivity, Aº, in units of S cm mol! d. Determine the equilibrium constant, Keq, for the dissociation reaction. Correctly using the units below will yield Keq in units of mol L'', and for a l M standard state, Key becomes unitless. (5 cm mol-)) 1/A (S-'cm mol) с А (S cmPL-) concentration, c (mol L-) 1.566 x 10- 2.600 x 10- 6.219 x 10- 10.441 x 10 (S cm ) 1.788 x 10 2.418 x 10-6 4.009 x 10-6 5.336 x 10-6

Answer 1

(CH3)4SnCl = (CH3)4Sn+ + C1-

According to Ostwald's dilution law,

------------------(1)

11. я Арка А3

Molar conductivity:

      ----------------------(2)

1000 =k

concentration (c) (mol/L)	$\kappa$ (S/cm)	$\lambda$ (S cm2 mol-1)	$\frac{1}{\lambda}$ (S-1 cm-2 mol)	$c\,\lambda$ (S cm2 L-1)
1.566*10-4	1.788*10-6	11.4176	0.08758	0.001788
2.600*10-4	2.418*10-6	9.3	0.1075	0.002418
6.219*10-4	4.009*10-6	6.446	0.1551	0.0040088
10.441*10-4	5.336*10-6	5.1106	0.1957	0.005336

111 10.201 10.15 0.10 0.05 LLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLUCA 0.0020 0.0025 0.0030 0.0035 0.0040 0.0045 0.0050

slope=30.37 S^-2 cm-⁴ L mol

Intercept=0.033586 S^-1 cm-² mol

From Eq. (1), one gets

k_eq=Intercept^2/slope=(0.033586 S^-1 cm-² mol)^2/(30.37 S^-2 cm-⁴ L mol)=3.714*10^-5 mol/L.