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A new drug has been found to be effective in treating 50% of the people afflicted...
A new drug has been found to be effective in treating 80% of the people afflicted...
A new drug has been found to be effective in treating 80% of the people afflicted by a certain disease. If the drug is administered to 300 people who have this disease, what are the mean and the standard deviation of the number of people for whom the drug can be expected to be effective? (Round your standard deviation to two decimal places.) mean: _____ people standard: _______ deviation people
A pharmaceutical company claims that a drug is effective in treating 90% of people having severe...
A pharmaceutical company claims that a drug is effective in treating 90% of people having severe migraine headaches. The drug is administed to 6 patients that have a severe migraine. What is the probability that exactly 5 people will have relief from their migraine? A. 0.354 B. 0.590 C. 0.059 D. 0.000054 What is the mean of the binomial distribution? A. 5.4 B. 5.6 C. 5.5 D. 0.54 What is the standard deviation of the binomial distribution? A. 0.27 B....
1. A certain medical test is known to detect 72% of the people who are afflicted...
1. A certain medical test is known to detect 72% of the people who are afflicted with the disease Y. If 10 people with the disease are administered the test, what is the probability that the test will show that: All 10 have the disease, rounded to four decimal places? .0374 At least 8 have the disease, rounded to four decimal places? At most 4 have the disease, rounded to four decimal places? Please show the steps in Microsoft excel...
2. Assume a pharmaceutical company invented a drug that is more effective in treating (or at...
2. Assume a pharmaceutical company invented a drug that is more effective in treating (or at least life extending) blood cancers and managed to obtain a patent on the drug making the company the sole provider of this blood cancer drug in the market for the next 30 years. Assume in the long-run (i.e.,in 30 years) as the patent expires, given a perfectly elastic long-run supply in the long-run, the competitive price becomes Pc, which also represents the industry’s marginal...
Assume the random variable X is normally distributed with mean equal to 50 and standard deviation...
Assume the random variable X is normally distributed with mean
equal to 50 and standard deviation of 7. Compute the probability.
Be sure to draw a normal curve with the area corresponding to the
probability shaded. P(35<x<58)
Assume the random variable X is normally distributed with mean u = 50 and standard deviation o= 7. Compute the probability. Be sure to draw a normal curve with the area corresponding to the probability shaded. P(35<X<58) Click the icon to view a...
Suppose X is a normal random variable with mean u = 50 and standard deviation o...
Suppose X is a normal random variable with mean u = 50 and standard deviation o = 11. (a) Compute the z-value corresponding to X = 36. (b) Suppose the area under the standard normal curve to the left of the Z-value found in part (a) is 0.1016. What is the area under the normal curve to the left of X = 36? (c) What is the area under the normal curve to the right of X = 36? (a)...
= 50 and standard deviation o = 7. Compute the probability. Be sure to draw a...
= 50 and standard deviation o = 7. Compute the probability. Be sure to draw a normal curve with Assume the random variable X is normally distributed with mean the area corresponding to the probability shaded. PIX> 36) Click the icon to view a table of areas under the normal curve. Which of the following normal curves corresponds to P(X> 36)? OA OB 36 50 36 50 36 50 PIX>36) = 0.6406 (Round to four decimal places as needed.)
Question 14 (5 points) Individuals who have a particular gene have a 0.61 probability of contracting...
Question 14 (5 points) Individuals who have a particular gene have a 0.61 probability of contracting a certain disease. Suppose that 1,389 individuals with the gene participate in a lifetime study. What is the standard deviation of the number of people who eventually contract the disease? Write only a number as your answer. Round to 2 decimal places (for example 1.56). Your Answer: Answer Question 15 (5 points) Find the area under the standard normal curve that lies between z-...
In a survey of 300 people, approximately 15% of the people identified themselves as being left-handed....
In a survey of 300 people, approximately 15% of the people identified themselves as being left-handed. What are the mean, standard deviation, and shape of the distribution of thesample proportion p-hat of respondents who say they are left-handed? (3 points) Using the normal approximation without the continuity correction, sketch theprobability distribution curve for the distribution of p-hat. Shade equal areas onboth sides of the mean to show an area that represents a probability of .95,and label the upper and lower...
In a survey of 300 people, approximately 15% of the people identified themselves as being left-handed....
In a survey of 300 people, approximately 15% of the people identified themselves as being left-handed. What are the mean, standard deviation, and shape of the distribution of thesample proportion p-hat of respondents who say they are left-handed? (3 points) Using the normal approximation without the continuity correction, sketch theprobability distribution curve for the distribution of p-hat. Shade equal areas onboth sides of the mean to show an area that represents a probability of .95,and label the upper and lower...
Assume the random variable X is normally distributed with mean
equal to 50 and standard deviation of 7. Compute the probability.
Be sure to draw a normal curve with the area corresponding to the
probability shaded. P(35<x<58)
Assume the random variable X is normally distributed with mean u = 50 and standard deviation o= 7. Compute the probability. Be sure to draw a normal curve with the area corresponding to the probability shaded. P(35<X<58) Click the icon to view a...
Suppose X is a normal random variable with mean u = 50 and standard deviation o = 11. (a) Compute the z-value corresponding to X = 36. (b) Suppose the area under the standard normal curve to the left of the Z-value found in part (a) is 0.1016. What is the area under the normal curve to the left of X = 36? (c) What is the area under the normal curve to the right of X = 36? (a)...
= 50 and standard deviation o = 7. Compute the probability. Be sure to draw a normal curve with Assume the random variable X is normally distributed with mean the area corresponding to the probability shaded. PIX> 36) Click the icon to view a table of areas under the normal curve. Which of the following normal curves corresponds to P(X> 36)? OA OB 36 50 36 50 36 50 PIX>36) = 0.6406 (Round to four decimal places as needed.)
Question 14 (5 points) Individuals who have a particular gene have a 0.61 probability of contracting a certain disease. Suppose that 1,389 individuals with the gene participate in a lifetime study. What is the standard deviation of the number of people who eventually contract the disease? Write only a number as your answer. Round to 2 decimal places (for example 1.56). Your Answer: Answer Question 15 (5 points) Find the area under the standard normal curve that lies between z-...
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