Question

Liquid hexane (CH,(CH).CH3) will react with gaseous oxygen (0,) to produce gaseous carbon diaxide (CO) and gaseous water (H,O), Suppose 0.862 g of hexane is mixed with 1.3 g of cxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 2 significant digits X

Answer 1

Solution Given : 0.862g of hexane is mixed with 1.39 CH3 CCH₂) 4 CH ₂ (1) + O2(g) H₂O(g) + Cao Balance the reaction : Co H14 Cl) +19 0269) — 7H2009) + 6C0218) Molar mass & CHI4 =6X 12 + 1481 - 12 + 1 =86 MDF Molen mass of os = 32g/mobor Moless of Cc H14 = 0,862 = 0.010 moles Moles of O2 = 13 = 0.0406 moles moles ratio - O2moles = 0.0406 C6 Hiu moleso lo Moles ratio - 4.06 And 1981 - 19 32

Hewe auording to the formula 19 :/ 9 moleu natio is ideal molar ratio Tue 0.010 moles o Co Hiy (0.8629). The amount of H₂O produces Мы[ои го и 2 к,0 = 1ва ме 6H, 0 : LC, Hig H2o produes! Модор Н, О. О.06ok 16 9 ма Недо 6x D. O | D = 0. 06омо/ - 1.08 9 Hel 1.08 Но домоди ER during this reaction.