2 C6H14 + 19 O2 = 12 CO2 + 14 H2O
Mole of hexane = 65.5 g /86 g/mol = 0.761 mol.
Mole of oxygen = 65 g / 32 g /mol = 2.03 mol.
For 19 mole Oxygen - - - - - 2 mole hexane
For 2.03 mole Oxygen - - - - - 0.214 mol hexane.
Excess hexane left = ( 0.761 - 0.214) = 0.547 mole
Mass of hexane leftover = mole × Molar mass
Mass = 0.547 mole × 86 g/mole = 47. 04 g
Liquid hexane (CH(CH).CH, will react with gaseous oxygen (0) to produce gaseous carbon dioxide (CO2) and...
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