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= STOCHOMETRY Limiting reactants Madelyn v Liquid hexane (CH, CH),CHwill react with gaseous oxygen (0) to produce gaseous car
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Answer #1

CH₂-(CH₃)4 CH₂ (g) +1902 6CO₂ +7H₂0 2 from above equation - 1 mole of he name required moles of ₂ - 19 I mole of hexane = 86g

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