Limiting reactants Liquid octane (CH,(CH) CH,) will react with gaseous oxygen (0) to produce gaseous carbon...

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Answer 1

Answer #1

Balanced equation:

2 C8H18 + 25 O2 $\rightarrow$ 16 CO2 + 18 H2O

Moles of Ocatane = mass / molar mass = 18.3 / 114 = 0.161 moles

Moles of O2 mass / molar mass = 84 / 32 = 2.625 moles

From the equation, mole sof O2 needed = moles of octane * 25 / 2 = 0.161 * 25 / 2 = 2.012 moles

Since there is more oxygen than needed, octane will completely react meaning miniumum leftover mass = 0 g

Answer 2

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