1)
[H+] = 2.19*10^-4 M
use:
pH = -log [H3O+]
= -log (2.19*10^-4)
= 3.6596
Answer: 3.7
2)
Molar mass of HCl,
MM = 1*MM(H) + 1*MM(Cl)
= 1*1.008 + 1*35.45
= 36.458 g/mol
mass(HCl)= 111.9 g
use:
number of mol of HCl,
n = mass of HCl/molar mass of HCl
=(1.119*10^2 g)/(36.46 g/mol)
= 3.069 mol
volume , V = 1.6*10^2 L
use:
Molarity,
M = number of mol / volume in L
= 3.069/1.6*10^2
= 1.918*10^-2 M
So,
[H+] = 1.918*10^-2 M
use:
pH = -log [H+]
= -log (1.918*10^-2)
= 1.7172
Answer: 1.7
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