Homework Answers
atomic mass of Fe = 55.845g/mole
molar mass of Fe2O3 = 159.69g/mole
Fe% = 2*atomic mass of Fe*100/molar mass of Fe2O3
= 2*55.845*100/159.69 = 69.94%
atomic mass of Fe = 55.845g/mole
molar mass of Fe3O4 = 231.533g/mole
Fe% = 3*atomic mass of Fe*100/molar mass of Fe3O4
= 3*55.845*100/231.533
= 72.4%
atomic mass of Fe = 55.845g/mole
molar mass of FeCO3 = 115.85g/mole
Fe% = 1*atomic mass of Fe*100/molar mass of FeCO3
= 1*55.845*100/115.85
= 48.2%
Fe3O4 has highest iron in the ore >>>answer
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A
0.1362g iron ore sample was dissolved in hydrochloric acid and the
iron was obtained as Fe^2+(aq). The iron solution was titrated with
Ce4+ solution according to the balanced chemical reaction shown
below. After calculation, it was found that 0.0238g of iron from
the ore reacted with the cerium solution.
Ce^4+(aq) + Fe 2+(aq) -> Ce^3+(aq) + Fe^3+(aq).
Calculate the mass percent of iron in the original ore sample.
Please round your answer to the tenths place.
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A
0.1362g iron ore sample was dissolved in hydrochloric acid and the
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Please round your answer to the tenths place.
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