Question

Problem 9.17 An intravenous saline solution contains 150 mEq/L each of Nat and Cl- All attempts used; correct answer displayed Part B How many moles of CT are in 1.40 L of the saline solution? CD A£¢ ROO? mol CI Submit Request Answer Provide Feedback

Answer 1

Let's see what we have ...

saline solution contains 150mEq/L

volume of saline solution= 1.40L

First we need to find out total mEq in 1.4 L solution.

* mEq is the unit which is used for electrolytes.

1 mEq is chemical activity given by 1 mgm of hydrogen or 23 mgm of sodium or 12 mgm of carbon.

If 1 L saline solution contains 150 mEq of Cl-

Then 1.4 L saline solution contains (?)

=( 1.4 L× 150 mEq ) / 1 L

= 210 mEq of Cl-

Now,

If 1 mEq represent 35.45 mgm of Cl-

Then 210 mEq represent (?)

= (210 mEq × 35.45 mgm) / 1 mEq

= 7444.5 mgm of cl-

= 7.444 gram of cl-

now,

moles of Cl- = gram of Cl- / molecular weight of Cl-

= 7.444 ( gram)/ 35.45 (gram/mole)

=0.21 moles

0.21 moles of Cl- are there in the 1.4 L saline solution.

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