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1)C) vs vdt 2) If Bob takes a trip and his displacement is given by the following equation x = (8 m/s)t + (2 m/s2)t2 A) Sketc
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Answer #1

The equation of motion of Bob tells that the Bob starts with speed 8m/s and moves with constant acceleration 1m/s.

Therefore the 3rd graph (Acceleration vs Time) will be a straight line parallel to time axis. It's intercept on acceleration axis will be 1m/s2

2nd Graph (Velocity vs Time) Will be a straight line with upward slope of 1 and intercept on velocity axis will be 8m/s

1st graph (Although not clear but I am assuming x vs time) will be an upward parabola with apex at the origin.

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