Question

As shown in the figure below, a small item is released from rest at point A along the horizontal diameter on the inside of a

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Answer #1

a)

Gravitational Potential energy at point A

PEA=mgR =0.155*9.81*0.33 = 0.50178 J

b)

Kinetic energy at point B is

KEB=0.50178 J

c)

(1/2)mVB2=0.50178

VB=sqrt[2*0.50178/0.155]=2.5445 m/s

d)

Kinetic energy at point C

KEC=mgR-mg(2R/3) =0.155*9.81*(0.33-(2/3)*0.33)

KEC=0.16726 J

E)

Potential energy at point C

PEC=mg(2R/3)=0.155*9.81*(2*0.33/3)=0.33452 J

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