what will the ph be for solution Q??
Solution C:
Millimoles of acetic acid = 3 mL * 0.5 mmol/mL = 1.5 mmol
Millimoles of sodium acetate = 15 mL * 0.5 mmol/mL = 7.5 mmol
Total volume = 3+15+12 = 30 mL
Solution Q:
10 mL of solution C contains 1.5/3 = 0.5 mmol of acetic acid, 7.5/3 = 2.5 mmol of sodium acetate.
Millimoles of NaOH = 10 mL * 0.1 mmol/mL = 1 mmol
The resulting millimoles of NaOH = 1-0.5 = 0.5 mmol
The resulting millimoles of sodium acetate = 2.5 + 0.5 = 3 mmol
Total volume = 10+10 = 20 mL
Now, [NaOH] = [OH-] = 0.5 mmol/20 mL = 0.025 M
Now, pOH = -Log[OH-] = -Log(0.025) = 1.6
Hence, pH = 14 - pOH = 14 - 1.6 = 12.4
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