Based on the Spectra, the compound is
1H-NMR of 2-bromopropane
2-bromopropane have two chemically different proton, first methyl proton give signal towards upfield around 1.4ppm, all six hydrogen are chemically equivalent, splitting pattern is doublet (2nI+1 = 2*1*1/2+1 =2) and another is methine proton which give signal towards downfield around 4.29 ppm, splitting pattern is multiplet (2nI+1 = 2*6*1/2+1 =7).
13C-NMR of 2-bromopropane
2-bromopropane has two chemically different carbon, one methyl carbon which shows signal around 30ppm and methine carbon shows peaks at 45ppm.
IR of 2-bromopropane:
IR spectrum of 2-bromopropane gives three stretching frequency
1. 2900 cm-1 for sp3 C-H stretching
2. 1200 cm-1 for C-C stretching
3. 650 cm-1 for C-Br stretching
Calculated Molecular weight of 2-bromopropane (using 79Br) = 122 g/mol
Given MW = 122 : 124 AMU 1:1
It shows that presence of isotopes with 1:1 ratio, Br isotopes has 100:99.9 ratio, so Br attach to the methine carbon.
Molecular formula of 2-bromopropane = C3H7Br
Lewis structure of C3H7Br:
For the following unknown, annotate the corresponding spetras and determine the molecular formula and lewis structure....
For the following unknown, annotate the corresponding spetras and determine the molecular formula and lewis structure. Unknown # s IR/HNMR/CNMR 1 MW= 88 AMU AVENUE S, 3 T, 1, 2] Broads, Ppm 200 160 140 180 120 80 40 60 20 ó 100 rpm
For the following unknown, annotate the corresponding spetras and determine the molecular formula and lewis structure. ииkи обои # IR HNMR/CNMR Мws 122 : 124 AMU 1:1 або зовоодо аbоооо
I need help figuring out what the molecular formula and structure look like based on the molecular weight 142 AMU and also based in the info given in the IR, HNMR, and CNMR. IR/HNMR/CNMR Unknown #101 MW=142 AMU Czol D2 | M 1 ppm 200 150 160 140 120 100 ao so 10 20 rpm
1. label all spectra in IR 2. figure out structure. label a,b,c,d, etc in structure and corresponding letter on all peaks in HMNR and CNMR 3. show all calculations IR/HNMR/CNMR MW=122: 124 AMU 1:1 11 10 200 150 160 140 120 100 ppm 100 0
Determine structure of unknown compound by deducing the formula and analyzing the spectra. Part C:S IR/HNMR/CNMR Unknown #93 MW=134 AMU / ring SOC-H dromul 5,311 - Overlapping Signals, 4 1,34 HEP-11-24 ppm 4 Signals 120-160 ppm 200 180 20-0-075 160 240 120 80 40 20 100 pon
1. label all spectra in IR 2. figure out structure. label a,b,c,d, etc in structure and corresponding letter on all peaks in HMNR and CNMR 3. show all calculations IR/HNMR/CNMR MW=122: 124 AMU 1:1 200 180 160 340 120 100 0 0 0
Part A: Make sure to write the labelled molecule structure on each 'HNMR and CNMR. Unknown #73: Annotate and assign the NMR Spectra of 5-chloro-2-pentanone: I m, 3H CH-CH2-CH2-CH - CH, m 3H m2H 11 10 9 8 7 6 5 1 HSP-00-414 ppm 10-09 Ci 6 b CH CH₂ CH₂ 1 1 CH₂ à el 1 СЕ О 60 40 200 200 180 160 140 120 100 30 ppm CDS-04-000
IR/HNMR/CNMR Unknown #102 MW-110 AMU 0 -H C=0 Wavenumber(em-1) Broads.s.2 3 overlapping signals, 4 FM EN ppm 20 0 200 180 160 12010030604020 rpm
On the following pages you will find problems of both HNMR and CNMR For each of the problems calculate the number of unsaturated sites, each set of peaks are already labeled A,B, C…, darw the proposed structure, and label the hydrogens appropriately. Example provided. Line drawings are fine Problem 7: CH20, U- 6122 δ 5.0, septet 82.3, q 6 1.3, d δ 1.2, t Draw structure and annotate BA 10 8 3 2 0 HSP-00-309 ppm Draw structure and annotate...
IR/HNMR/CNMR Unknown #25 MW-88 AMU Sp3 C-H 5,3 CH - Co- 6 ppm cha 3 .ca CH₂ - do 6 CH 3 180 150 140 120 100 rpm 80 60 40 20