THe above spectrum corresponds to CH3CH2CH2OCH2CH2CH3
Molecular Formula: C6H14O
THe 1H NMR shows a triplet at 1 ppm corresponds to CH3 protons because of the adjacent CH2 group. A multiplet is observed at 1.8 ppm because of the adjacent CH3 and CH2 groups. The triplet at 3.3 ppm is downshielded because of the presence of Oxygen group and adds up to 2 proton.
The IR spectrum did not show the presence of OH stretching or carboxylic group (absent in 13C as well). The 3000 cm-1 corresponds to alkyl stretching groups.
For the following unknown, annotate the corresponding spetras and determine the molecular formula and lewis structure....
For the following unknown, annotate the corresponding spetras and determine the molecular formula and lewis structure. Anknown IR/HNMR/CNMR MW=122 : 124 AMU 1:1 D 3000 1000 00 RYENUEERI D, 6 M, 1 10 7 4 1 HP-03-172 Ppm N 10 120 60 100 80 40 20 200 180 160 140 ppm CDS-00-26O
For the following unknown, annotate the corresponding spetras and determine the molecular formula and lewis structure. Unknown # s IR/HNMR/CNMR 1 MW= 88 AMU AVENUE S, 3 T, 1, 2] Broads, Ppm 200 160 140 180 120 80 40 60 20 ó 100 rpm
I need help figuring out what the molecular formula and structure look like based on the molecular weight 142 AMU and also based in the info given in the IR, HNMR, and CNMR. IR/HNMR/CNMR Unknown #101 MW=142 AMU Czol D2 | M 1 ppm 200 150 160 140 120 100 ao so 10 20 rpm
Determine structure of unknown compound by deducing the formula and analyzing the spectra. Port C :3 IR/HNMR/CNMR Unknown #22 MW=136 AMU ficco 2000 de HUMA TMS 3 overlapping signals, 5 LAN COCI3(solvent TTMS 100 100 BD RCH3
1. label all spectra in IR 2. figure out structure. label a,b,c,d, etc in structure and corresponding letter on all peaks in HMNR and CNMR 3. show all calculations IR/HNMR/CNMR MW=122: 124 AMU 1:1 200 180 160 340 120 100 0 0 0
1. label all spectra in IR 2. figure out structure. label a,b,c,d, etc in structure and corresponding letter on all peaks in HMNR and CNMR 3. show all calculations IR/HNMR/CNMR MW=122: 124 AMU 1:1 11 10 200 150 160 140 120 100 ppm 100 0
Determine structure of unknown compound by deducing the formula and analyzing the spectra. Part C:S IR/HNMR/CNMR Unknown #93 MW=134 AMU / ring SOC-H dromul 5,311 - Overlapping Signals, 4 1,34 HEP-11-24 ppm 4 Signals 120-160 ppm 200 180 20-0-075 160 240 120 80 40 20 100 pon
b. An unknown compound has the molecular formula ChHsO2. Draw a structure of the unknown that is consistent with the IR spectrum below. Label the peaks on the spectra with the corresponding functional groups that you used to determine your structure. 100 50 2008 1000 580 4000 2000
for part a I need how to determine and draw the molecular formula part c and d is for the hnmr nad cnmr Compound 5: Use the information provided below and the IR and NMR spectra on the next page to answer the following questions. a) An MS was taken of compound 5 and the table is given below. Determine the molecular formula of 5 from the MS given below. relative abundance 138 33.3 139 m/z 2.9 b) Calculate the...
draw the structure with the molecular formula C9H12. Use the IR and HNMR data below IR absorption at 2850-3150cm-1. Click the draw structure button to launch the drawing utility. Draw the structure with the molecular formula C9H12. Use the IR and HNMR data below. IR absorption at 2850-3150 cm^-1