Question

IR/HNMR/CNMR Unknown #25 MW-88 AMU Sp3 C-H 5,3 CH - Co- 6 ppm cha 3 .ca CH₂ - do 6 CH 3 180 150 140 120 100 rpm 80 60 40 20

Answer 1

The IR Absorption at arounc Bcoo cm C-H shrutehing is due to the 1690-170 cil The IR Absorpticn at around is due to the predence of 0haus The 1R absorptien at cmound 1BD - |lco due c-o shrehing to NMR - The PmR singlet at 2.2d Coresponding to 3 protorn Shouos XCH3 It is clishi lcleal due to the presence of Carbony/ cmaco The pmR Singlet at 3.45 S correoponding to aproton 0-CH3 Shows be atteeheo! to he It elishileal due h Gxygen The pmR singlet at 4156 Corespondfnq to 2 *-CHX It is Proton CmR 28 CH3 GO -CH3 80 -CH2 220

from above Dede , Hhe Shultene of organic ccmpound 8a4 Ct2 6 0 28 CH3 сHge 3.45d Cs) 226 Cs) 4.ISCd)