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Consider a galvanic cell based on the following half reactions: E° (V) Mg2+ + 2e +...
Consider a galvanic cell based on the following half reactions: E° (V) Zn2+ + 2e →...
Consider a galvanic cell based on the following half reactions: E° (V) Zn2+ + 2e → Zn -0.76 Au?+ + 3e → Au 1.50 If this cell is set up at 25°C with [Zn2] = 1.00 x 10-4M and [Au?') -2.00 10-2M, the expected cell potential is Submit Hide Hints Hint 1 Hint 2 The Nernst equation is based on the balanced cell reaction. Q reflects the mass action expression for the balanced cell reaction and n is the number...
A galvanic cell is based on the following half reactions E° (V) Au33e Au 1.50 Mg22e...
A galvanic cell is based on the following half reactions E° (V) Au33e Au 1.50 Mg22e Mg -2.37 Calculate the standard potential for this cell V This cell is set up at 25°C with [Mg2 ]= 1.00 x 10-M The cell potential is observed to be 3.97 V. Calculate the [Au3*] that must be present (Enter your answer to three significant figures.) [Au3 Submit Hide Hints Hint 2 Hint 1 Hint 3 Write the Nernst equation for the cell reaction....
Given the following half reactions what is the voltage of the galvanic cell that would result...
Given the following half reactions what is the voltage of the galvanic cell that would result from their combination [maximum positive voltage and spontaneous reaction). Show work. E° (volts) -0.74 Cr3+ (aq) + 3e Cu2+ (aq) + 2e → → Cr (8) Cu (s) +0.34 And what is the overall reaction that results after the half reactions are combined to cancel all electrons. Show work. And fill in the following abbreviated cell to represent the actual galvanic cell from above.
Fill in the Blanks 0.34 Half Reaction E. (V) Half Reaction Erd® (V) F + 2e...
Fill in the Blanks 0.34 Half Reaction E. (V) Half Reaction Erd® (V) F + 2e →2F 0+ 2H + 2e →H,02 0.68 Ag* + e → Ag Cu* + e → Cu 0.52 Co? + e Co? O2 + 2H,0 + 4e → 40H 0.40 H,O, + 2H + 2e → 2H,0 Cu2+ + 2e → Cu Cet+e → Ces Cu2+ + e → Cut 0.16 PbO, + 4H+ +50,2 +2e → PbSO, + 2H,0 2H* + 2e →...
Consider the following half-reactions: Half-reaction E° (V) 12(s) + 2e - →21"(aq) 0.535V 2H+ (aq) +...
Consider the following half-reactions: Half-reaction E° (V) 12(s) + 2e - →21"(aq) 0.535V 2H+ (aq) + 2e - → H2(g) 0.000V Cr3+(aq) + 3e —— Cr(s) -0.740V The strongest oxidizing agent is: enter formula The weakest oxidizing agent is: The weakest reducing agent is: The strongest reducing agent is: Will 12(s) reduce Cr3+(aq) to Cr(s)? — Which species can be reduced by H2(g)? If none, leave box blank. Use the References to access important values if needed for this question....
Consider the following half-reactions: Half-reaction E° (V) F2(g) +2e - →2F (aq) 2.870V 2H*(aq) + 2e...
Consider the following half-reactions: Half-reaction E° (V) F2(g) +2e - →2F (aq) 2.870V 2H*(aq) + 2e - H2(g) 0.000V Cr3+ (aq) + 3e — Cr(s) -0.740V (1) The strongest oxidizing agent is: enter formula (2) The weakest oxidizing agent is: (3) The weakest reducing agent is: (4) The strongest reducing agent is: (5) Will F2(g) oxidize Cr(s) to Cr3+ (aq)? (6) Which species can be oxidized by H(aq)? If none, leave box blank.
A galvanic cell based on the following reactions Cu 2+ (aq) + 2e- + Cu(s) E°=0.339...
A galvanic cell based on the following reactions Cu 2+ (aq) + 2e- + Cu(s) E°=0.339 V (AD + 14H(aq) + 6e-4 2Cr 3+(aq) + 7 H2O(1) Eo=1.330 V a) Write the overall cell reaction and determine its voltage. b) If the E value of the galvanic cell is 1.2 le of the galvanic cell is 1.254 V, calculate the pH of the cell when [Cu2+]=0.00010 M, Cr-0,2-1=0.00460 M, Cr3+1=1.0x102 M. The Nerst equation is E=E - (0.0592/n)logQ
A chemist designs a galvanic cell that uses these two half-reactions: standard reduction potential half-reaction +...
A chemist designs a galvanic cell that uses these two half-reactions: standard reduction potential half-reaction + O2(9)+4 H (aq)+4e' 2H20) = 1.23 V red Ered Fe+. (аq) Fe3(aq)+e = +0.771 V Answer the following questions about thiss cell Write a balanced equation for the half-reaction that happens at the cathode Write a balanced equation for the half-reaction that happens at the anode Write a balanced equation for the overall reaction that powers the cell. Be sure the reaction is spontaneous...
help with these please Consider the following half-reactions: Half-reaction Eo (V) F2(g)+ 2e 2F (aq) 2.870V...
help with these please
Consider the following half-reactions: Half-reaction Eo (V) F2(g)+ 2e 2F (aq) 2.870V Sn2 (aq) + 2e- Sn(s) 0.140V Cr3 (aq) + 3e° _ Cr(s)-0.740V (1) The strongest oxidizing agent is: enter formula (2) The weakest oxidizing agent is: (3) The weakest reducing agent is: (4) The strongest reducing agent is: (5) Will F2(g) oxidize Cr(s) to Cr3 (aq)? (6) Which species can be oxidized by Sn2 (aq)? If none, leave box blank. Consider the following half-reactions:...
Standard reduction half-cell potentials at 25°C E (V) E (V) 1.50 -0.45 0.80 -0.50 0.77 -0.73...
Standard reduction half-cell potentials at 25°C E (V) E (V) 1.50 -0.45 0.80 -0.50 0.77 -0.73 0.52 -0.76 0.34 -1.18 Half-reaction Aut (aq) + 3e +Au(s) Ag+ (aq) + +Ag(s) Fe3+ (aq) +34 Fo+ (aq) Cut(aq) + Cu(s) Cu²+ (aq) + 2e +Cu(s) 2H+ (aq) - 2e +H2 (6) Fe3+ (aq) + 3e Fe(s) Pb2+ (aq) + 2e →Pb(s) Sn-(aq) + 2e +Sn(s) Ni2+ (aq) + 2e →Ni(s) Co2(aq) +2e + Co(s) ca? (aq) + 2e +Cd(s) 0.00 Half-reaction Fe(aq)...
Consider a galvanic cell based on the following half reactions: E° (V) Zn2+ + 2e → Zn -0.76 Au?+ + 3e → Au 1.50 If this cell is set up at 25°C with [Zn2] = 1.00 x 10-4M and [Au?') -2.00 10-2M, the expected cell potential is Submit Hide Hints Hint 1 Hint 2 The Nernst equation is based on the balanced cell reaction. Q reflects the mass action expression for the balanced cell reaction and n is the number...
A galvanic cell is based on the following half reactions E° (V) Au33e Au 1.50 Mg22e Mg -2.37 Calculate the standard potential for this cell V This cell is set up at 25°C with [Mg2 ]= 1.00 x 10-M The cell potential is observed to be 3.97 V. Calculate the [Au3*] that must be present (Enter your answer to three significant figures.) [Au3 Submit Hide Hints Hint 2 Hint 1 Hint 3 Write the Nernst equation for the cell reaction....
Given the following half reactions what is the voltage of the galvanic cell that would result from their combination [maximum positive voltage and spontaneous reaction). Show work. E° (volts) -0.74 Cr3+ (aq) + 3e Cu2+ (aq) + 2e → → Cr (8) Cu (s) +0.34 And what is the overall reaction that results after the half reactions are combined to cancel all electrons. Show work. And fill in the following abbreviated cell to represent the actual galvanic cell from above.
Fill in the Blanks 0.34 Half Reaction E. (V) Half Reaction Erd® (V) F + 2e →2F 0+ 2H + 2e →H,02 0.68 Ag* + e → Ag Cu* + e → Cu 0.52 Co? + e Co? O2 + 2H,0 + 4e → 40H 0.40 H,O, + 2H + 2e → 2H,0 Cu2+ + 2e → Cu Cet+e → Ces Cu2+ + e → Cut 0.16 PbO, + 4H+ +50,2 +2e → PbSO, + 2H,0 2H* + 2e →...
Consider the following half-reactions: Half-reaction E° (V) 12(s) + 2e - →21"(aq) 0.535V 2H+ (aq) + 2e - → H2(g) 0.000V Cr3+(aq) + 3e —— Cr(s) -0.740V The strongest oxidizing agent is: enter formula The weakest oxidizing agent is: The weakest reducing agent is: The strongest reducing agent is: Will 12(s) reduce Cr3+(aq) to Cr(s)? — Which species can be reduced by H2(g)? If none, leave box blank. Use the References to access important values if needed for this question....
Consider the following half-reactions: Half-reaction E° (V) F2(g) +2e - →2F (aq) 2.870V 2H*(aq) + 2e - H2(g) 0.000V Cr3+ (aq) + 3e — Cr(s) -0.740V (1) The strongest oxidizing agent is: enter formula (2) The weakest oxidizing agent is: (3) The weakest reducing agent is: (4) The strongest reducing agent is: (5) Will F2(g) oxidize Cr(s) to Cr3+ (aq)? (6) Which species can be oxidized by H(aq)? If none, leave box blank.
A galvanic cell based on the following reactions Cu 2+ (aq) + 2e- + Cu(s) E°=0.339 V (AD + 14H(aq) + 6e-4 2Cr 3+(aq) + 7 H2O(1) Eo=1.330 V a) Write the overall cell reaction and determine its voltage. b) If the E value of the galvanic cell is 1.2 le of the galvanic cell is 1.254 V, calculate the pH of the cell when [Cu2+]=0.00010 M, Cr-0,2-1=0.00460 M, Cr3+1=1.0x102 M. The Nerst equation is E=E - (0.0592/n)logQ
A chemist designs a galvanic cell that uses these two half-reactions: standard reduction potential half-reaction + O2(9)+4 H (aq)+4e' 2H20) = 1.23 V red Ered Fe+. (аq) Fe3(aq)+e = +0.771 V Answer the following questions about thiss cell Write a balanced equation for the half-reaction that happens at the cathode Write a balanced equation for the half-reaction that happens at the anode Write a balanced equation for the overall reaction that powers the cell. Be sure the reaction is spontaneous...
help with these please
Consider the following half-reactions: Half-reaction Eo (V) F2(g)+ 2e 2F (aq) 2.870V Sn2 (aq) + 2e- Sn(s) 0.140V Cr3 (aq) + 3e° _ Cr(s)-0.740V (1) The strongest oxidizing agent is: enter formula (2) The weakest oxidizing agent is: (3) The weakest reducing agent is: (4) The strongest reducing agent is: (5) Will F2(g) oxidize Cr(s) to Cr3 (aq)? (6) Which species can be oxidized by Sn2 (aq)? If none, leave box blank. Consider the following half-reactions:...
Standard reduction half-cell potentials at 25°C E (V) E (V) 1.50 -0.45 0.80 -0.50 0.77 -0.73 0.52 -0.76 0.34 -1.18 Half-reaction Aut (aq) + 3e +Au(s) Ag+ (aq) + +Ag(s) Fe3+ (aq) +34 Fo+ (aq) Cut(aq) + Cu(s) Cu²+ (aq) + 2e +Cu(s) 2H+ (aq) - 2e +H2 (6) Fe3+ (aq) + 3e Fe(s) Pb2+ (aq) + 2e →Pb(s) Sn-(aq) + 2e +Sn(s) Ni2+ (aq) + 2e →Ni(s) Co2(aq) +2e + Co(s) ca? (aq) + 2e +Cd(s) 0.00 Half-reaction Fe(aq)...
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