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A galvanic cell is based on the following half reactions E° (V) Au33e Au 1.50 Mg22e Mg -2.37 Calculate the standard potential

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(RP) We have quen Reducing rotential of Au and mg U and RP is greater for Au so it will reduc in cellrxh and my will oxldse IEcev = (2.37 +1:50) v * Ecl1 = 3.87 V. 3.87N 30927_+ 2 Aulst Tags P som standard potential of Cel) = 3.87v - здеу + 4 Aya) е-_and (My24) = 1810-5M so Ecell = Erell - 0.06 loga 3.97 - 3187 – 0.06 tag @ 0.12 -0.01 log & - -10 = 109 Q TQ = 10-10 Img+27[A13+)? = [ Mg2+1? 10-10 [ 1410-51 To-to- [Au 3+1 = 10-5 SAU3+] = 0.00316 M AU3+ = 3.16 x 10-3M

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